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4 years ago

PLZ HURRY DIS IS TIMED !!!

Mathematics

1 answer:

Iteru [2.4K]4 years ago

4 0

Answer:

0-5 is 4, 6-10 is 2, 11-15 is 6, and 16-20 is 1

Step-by-step explanation:

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The perpendicular bisectors of ΔPQR intersect at point A as shown in the diagram. What is the radius of the circumscribed circle

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The answer to this is 9.22

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3 years ago

PLS HELP ME I RLY DO NEED HELP

Nataly_w [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Vladimir79 [104]

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2 years ago

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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

<u><em>Solved</em></u>

6 0

3 years ago

I need this to be 20 letters so whats 2 +2

Firdavs [7]

Answer: So what is two plus two plus two?

Well let me demonstrate. Take 2 cookies for example, your friend supplements 2 more cookies and there you have it 4 cookies. So two and two cookies are 4 cookies. Thus, 2+2=4

Step-by-step explanation: Hope I helped you out <3

-Carrie

5 0

3 years ago