Step-by-step explanation:
∫₀³⁰ (r/V C₀ e^(-rt/V)) dt
If u = -rt/V, then du = -r/V dt.
∫ -C₀ e^u du
-C₀ ∫ e^u du
-C₀ e^u + C
-C₀ e^(-rt/V) + C
Evaluate between t=0 and t=30.
-C₀ e^(-30r/V) − -C₀ e^(-0r/V)
-C₀ e^(-30r/V) + C₀
C₀ (-e^(-30r/V) + 1)
I got the same answer. Try changing the lowercase v to an uppercase V.
Make more sense ou of this question and I can help you out more ok?
If you mean the one is repeating as 2.1111111....
You would write the decimal as a mixed number of 2 and 1/9 as 1/9 would equal to the 0.1111111.
Hope that helps!
Answer:
C
Step-by-step explanation:
We want the equation of the line that passes through (3, 6) and is perpendicular to:

First, convert the second equation into slope-intercept form:

So, we can see that the slope of the line is 3/4.
The slopes of perpendicular lines are negative reciprocals of each other.
Therefore, the slope of the new line is -4/3.
It passes through the point (3, 6).
We can use the point-slope form:

Substitute:

Distribute:

Therefore:

The answer is C.