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avanturin [10]
3 years ago
10

Let me know if you know the answer to this thank you​

Mathematics
1 answer:
Alexus [3.1K]3 years ago
3 0

We know

\boxed{\sf \dfrac{a^m}{a^n}=a^{m-n}}

\\ \sf\longmapsto \dfrac{1\times 10^{-5}}{2\times 10^{-1}}

\\ \sf\longmapsto 0.5\times 10^{-5-1}

\\ \sf\longmapsto 0.5\times 10^{-6}

\\ \sf\longmapsto 5\times 10^{-7}

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Suppose the probability that a softball player gets a hit in any single at-bat is 0.300. Assuming that her chance of getting a h
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Answer:

P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

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Solution to the problem

For this case we want this probability

P(X=4)

And using the probability mass function we got:

P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

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