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leonid [27]
3 years ago
15

How many solutions does the equation 6(x -2) = 8 + 6x have?

Mathematics
1 answer:
Contact [7]3 years ago
7 0

Answer:

There are no solutions.

Step-by-step explanation:

First simplify the equation.

<u>6(x - 2)</u> = 8 + 6x

Distribute.

6x - 12 = 8 + 6x

Adding 8 to a number and subtracting 12 from the same number to get the same answer doesn't make sense so there are no solutions.

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Ke Shawn is placing a right triangle in the coordinate plane. He knows that the longer leg is twice the length of the shorter le
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the 3rd vertex is on the x axis line which means Y =0

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 so the 3rd vertex is (2a,0)

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3 years ago
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How long will it take a $800 investment to be worth $900 if it is continuously compounded at 11% per year?
Kruka [31]
The formula is
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3 years ago
Which word problem correctly uses the expression 3/4 ÷ 1/8 ?
jonny [76]
I believe the answer is D since each bracelet would be 1 of 8.
3 0
3 years ago
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Pedro was curious if circles a and b with x and y Being on a circle respectively with similar so he tried to math one figure ont
tatuchka [14]

Answer:

The strategy Pedro tend to do isn't worth, because using rigid transformation to place on figure onto the other won't prove that those figures are similar, but it would prove if they are congruent.

Remember that similarity is about proportionality between dimensions of those figures, so it's not about congruence. That means the figures won't match when we place one onto the other.

To prove similarity, Pedro should divide each pair of corresponding coordinate, if all divisions give the same result, that means those figures are similar.

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3 0
3 years ago
The equation a = StartFraction one-half EndFraction left-parenthesis b 1 plus b 1 right-parenthesis.(b1 + b2)h can be used to de
aleksley [76]

Answer:

The equivalent expressions are:

b1=\frac{2a}{h}-b2

h=\frac{2a}{b1+b2}

Step-by-step explanation:

Given equation for finding area of a trapezoid:

a=\frac{1}{2}(b1+b2)h\\

where a represents area, h represents height and b1\ and\ b2 represents the base lengths of the trapezoid.

Evaluating h by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

2\times a=2\times\frac{1}{2}(b1+b2)h

2a=(b1+b2)h

Dividing both sides by b1+b2

\frac{2a}{b1+b2}=\frac{(b1+b2)h}{b1+b2}

\frac{2a}{b1+b2}=h

\therefore h=\frac{2a}{b1+b2}

Evaluating b1 by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

2\times a=2\times\frac{1}{2}(b1+b2)h

2a=(b1+b2)h

Dividing both sides by h

\frac{2a}{h}=\frac{(b1+b2)h}{h}

\frac{2a}{h}=b1+b2

Subtracting both sides by b2

\frac{2a}{h}-b2=b1+b2-b2

\frac{2a}{h}-b2=b1

\therefore b1=\frac{2a}{h}-b2

8 0
3 years ago
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