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Blizzard [7]
2 years ago
6

in a bag of candies there are `3 red candies, 13 green candies, 13 yellow candies, and 13 blue candies. If you choose 1 candy fr

om the bag, what is the probability the candy will not be blue
Mathematics
1 answer:
rodikova [14]2 years ago
8 0

Answer:

29/42

Step-by-step explanation:

No. of red candies = 3

No. of green candies = 13

No. of yellow candies = 13

No. of blue candies = 13

T.T = 42

Probability that candy will not be blue= 13+13+3 = 29

= 29/42

Hope it helps!

Pls mark me brainliest

Have a good day.

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As we can see this line hits the y-axis at (0,3)-->> y-intercept=3

Thus, your answer.
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A company tests the life of its rechargeable batteries over six months of use. They test how long a battery will last after a fu
jonny [76]

Answer:

18.6 months

Step-by-step explanation:

Given that :

Best fit line from scatterplot :

y=-12.05x +224.26

x = Number of month

y = charge on battery

Number of months a typical battery uses before being dead completely :

When battery is dead completely ; charge =0, y = 0

y = -12.05x + 224.26

0 = - 12.05x + 224.26

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4 0
2 years ago
. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an
Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when X = 59.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{59.5 - 56}{1.12}

Z = 3.1

Z = 3.1 has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

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3 years ago
Explain why you rename 4 1/4 to find 4 1/4- 3/4​
Hitman42 [59]

Answer:

Because it is a mixed fraction and it should be renamed in order to solve your problem, for the other one CAN NOT be converted into a mixed fraction.

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2 years ago
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