Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
Answer: 18
Step-by-step explanation:
Answer: the other two sides are 5 feet and 12 feet
Step-by-step explanation:
Length of one side be x , that means the other side is x + 7
by Pythagoras theorem:
+
= 
expanding , we have:
+
+ 14x + 49 = 169
+ 14x + 49 - 169 = 0
+ 14x - 120 = 0
divide through by 2 , we have
+ 7x - 60 = 0
By factorizing , we have
(x - 5)(x+12) = 0
Therefore:
x = 5 or x = -12
Since , the side can not be negative , so
x = 5
That means the other side will be 5+ 7 = 12
What in the world is that