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Blizzard [7]
2 years ago
6

in a bag of candies there are `3 red candies, 13 green candies, 13 yellow candies, and 13 blue candies. If you choose 1 candy fr

om the bag, what is the probability the candy will not be blue
Mathematics
1 answer:
rodikova [14]2 years ago
8 0

Answer:

29/42

Step-by-step explanation:

No. of red candies = 3

No. of green candies = 13

No. of yellow candies = 13

No. of blue candies = 13

T.T = 42

Probability that candy will not be blue= 13+13+3 = 29

= 29/42

Hope it helps!

Pls mark me brainliest

Have a good day.

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Step-by-step explanation:

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3 years ago
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expeople1 [14]
Simplifying
x + 0.7 = 1 + -0.2x

Reorder the terms:
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Solving
0.7 + x = 1 + -0.2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '0.2x' to each side of the equation.
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0.7 + 1.2x = 1 + -0.2x + 0.2x

Combine like terms: -0.2x + 0.2x = 0.0
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0.7 + 1.2x = 1

Add '-0.7' to each side of the equation.
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Combine like terms: 1 + -0.7 = 0.3
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Simplifying
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I only know 1 way.
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skelet666 [1.2K]

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Step-by-step explanation:

got it right on edmentum I am a smart mf

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