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Soloha48 [4]
3 years ago
5

What should i do now? did i do something wrong?

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
8 0

6 x -3 = -18 not +18

6(5x-3)-2

30x - 18- 2

30x -20

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Multiply your outside number and your answer to see if you got the number inside the box
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4 - x + <img src="https://tex.z-dn.net/?f=6%5E%7B2%7D" id="TexFormula1" title="6^{2}" alt="6^{2}" align="absmiddle" class="latex
Lemur [1.5K]

Answer:

x ≤ 19

Step-by-step explanation:

The instructions here are probably "solve for x."  Please include them.

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becomes 4 - x + 36 ≥  21

Now combine like terms.  4 and 36 combine to 40:  40 - x ≥ 21, and so:

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Adding x to both sies results in

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Please, include the instructions when you post a question.  Thanks.

3 0
3 years ago
In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square?
Shkiper50 [21]
Hello :
f(x) = 4(x2 − 6x + 3² - 3²____) + 20 = 4((x2 − 6x + 3²) - 3²____) + 20<span>
      = 4(x-3)² -36+20
</span>f(x) = 4(x-3)² -16 (vertex form)

6 0
3 years ago
I need answer how to do number 3
Olegator [25]
You know that you need two already to make one hexagon. So, if you multiply, or add two four times, 2+2+2+2, you would get eight.
3 0
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Read 2 more answers
Help with number 6 pleaseeeeeeee
vitfil [10]
SinA=5root3/10
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CosC=5root3/10
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7 0
3 years ago
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