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Cada caja contiene el mismo número de cuadernos. Si Mario transporta 120 cuadernos en total en una carretilla, ¿cuántos cuaderno

DIA [1.3K]

Answer:

Se almacena un cuaderno por caja, significando 120 cuadernos en 120 cajas iguales.

Step-by-step explanation:

A partir del enunciado, podemos calcular el número de cuadernos por caja al dividir el total de cuadernos en la carretilla por el número de cajas disponibles.

$x = \frac{120\,cuadernos}{120\,cajas}$

$x = 1\,\frac{cuadernos}{caja}$

Se almacena un cuaderno por caja, significando 120 cuadernos en 120 cajas iguales.

3 0

3 years ago

Write the equations included in the same set of related facts as 6x8=48

lisabon 2012 [21]

I think it is 16·3=48

8 0

3 years ago

Read 2 more answers

A survey of couples in a city found the following probabilities:

liraira [26]

Answer

(a) 0.94

(b)0.06

Step-by-step explanation:

P(husband is employed) = P(H) = 0.85

P(wife is employed) = P(W) = 0.59

P(both are employed) = P(H∩W) = 0.50

(a) At least one of them is employed

= P(H∪W)

= P(H) + P(W) - P(H∩W)

=0.85 + 0.59 - 0.50

=0.94

(b) Neither is employed,

=1 - P(H∪W)

= 1-0.94

=0.06

8 0

2 years ago

THE BASE AND HEIGHT OF A TRIANGLE WHOSE HEIGHT IS FIVE MORE THAN 6 TIMES ITS BASE

Sedaia [141]

X by 6 then add it all togeth

8 0

3 years ago

Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f

tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :- f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x) to have a maximum or minimum at given point.

ii) find first derivative $f^{l} (x)$ and equating zero

iii) solve and find 'x' values

iv) Find second derivative $f^{ll}(x) >0$ then find the minimum value at x=a

v) Find second derivative $f^{ll}(x)$ then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

step1:- find first derivative $f^{l} (x)$ and equating zero

$f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)$

$f^{l}(x) = \frac{1}{x^2+1} (2x)$ ……………(1)

$f^{l}(x) = \frac{1}{x^2+1} (2x)=0$

the point is x=0

step2:-

Again differentiating with respective to 'x', we get

$f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}$

on simplification , we get

$f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}$

put x= 0 we get $f^{ll}(0) = \frac{2}{(1)^2}$ > 0

$f^{ll}(x) >0$ then find the minimum value at x=0

Final answer:-

The minimum value of the given function is f(0) = 0

5 0

3 years ago