The slope of any function is its first derivative.
If f(x)=x^2, then f'(x)= 2x .
At x=5, slope = f'(x) = 2(5) = <em>10</em> .
Answer:
The answer is 18p^3r and 63p^3
Step-by-step explanation:
G.C.F of 18p^3 r and 45p^4q is = 9p^3
18p^3r = 2*3*3*p*p*p*r
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
G.C.F of 63p^3 and 45p^4q is = 9p^3
63p^3 = 3*3*7*p*p*p
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
Therefore the answer is 18p^3r and 63p^3....
Answer:
then what?
Step-by-step explanation:
do we have to find the angle?
all I know is every right triangle is equal to 90°
