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2 years ago

Please help! this the last question

Mathematics

2 answers:

Ksenya-84 [330]2 years ago

7 0

Answer: A
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valentinak56 [21]2 years ago

4 0

It’s C. I have to put more letters just ignore this

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The smaller triangle is the image of the larger triangle after a dilation. The center of the dilation is (4,2).

vlabodo [156]

Answer:

-1/3

Step-by-step explanation:

Take the ratio of the corresponding sides to get the scale factor so for this equation let's use the hypotenuse.

The length of the hypotenuse of the larger triangle is 12 units and the smaller triangle's hypotenuse is 4 so 4/12 is the scale factor.

However 4/12 can be simplified down to 1/3.

Since the smaller triangle has been flipped upside down the scale factor is negative so the final answer is -1/3

8 0

3 years ago

Vincent has the following data:

Igoryamba

Step-by-step explanation:

it is 18 because 18 is greater than 17 and my aunt is a teacher and told me the answer

4 0

2 years ago

PLEASE HELP FOR A COOKIE

nikdorinn [45]

Create a ratio and cross multiply

20x - 75 = 14x + 63
6x = 138
x=23

hope this helps :)

6 0

3 years ago

The domain of startfraction f over g endfraction f g consists of numbers x for which g left parenthesis x right parenthesisg(x)

Misha Larkins [42]

The domain of f/g consists of numbers x for which g(x) cannot equal 0 that are in the domains of both f and g.

Let’s take this equation as an example:

If f(x) = 3x - 5 and g(x) = square root of x-5, what is the domain of (f/g)x.

For x to be in the domain of (f/g)(x), it must be in the domain of f and in the domain of g since (f/g)(x) = f(x)/g(x). We also need to ensure that g(x) is not zero since f(x) is divided by g(x). Therefore, there are 3 conditions.

x must be in the domain of f: f(x) = 3x -5 are in the domain of x and all real numbers x.

x must be in the domain of g: g(x) = √(x - 5) so x - 5 ≥ 0 so x ≥ 5.

g(x) can not be 0: g(x) = √(x - 5) and √(x - 5) = 0 gives x = 5 so x ≠ 5.

Hence to x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x satisfying x > 5.

Thus, satisfying <span>satisfy all three conditions, x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x satisfying x > 5.</span>

5 0

3 years ago

Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

6 0

3 years ago