Angle AOC = 46° Find angle BPO
We have congruent right triangles PAO and PBO, right angles A and B.
So AOC=BOC=46 degrees,
PBO is a right angle so BPO is complementary to BOC, so 42 degrees
Answer: 42 degrees
The solution is ![(1,1)](https://tex.z-dn.net/?f=%281%2C1%29)
Step-by-step explanation:
The system of linear equation is
and ![y+\frac{1}{3} y=\frac{4}{3}](https://tex.z-dn.net/?f=y%2B%5Cfrac%7B1%7D%7B3%7D%20y%3D%5Cfrac%7B4%7D%7B3%7D)
Using substitution method, let us substitute
in the equation
![y+\frac{1}{3} y=\frac{4}{3}](https://tex.z-dn.net/?f=y%2B%5Cfrac%7B1%7D%7B3%7D%20y%3D%5Cfrac%7B4%7D%7B3%7D)
![-3 x+4+\frac{1}{3}(-3 x+4)=\frac{4}{3}](https://tex.z-dn.net/?f=-3%20x%2B4%2B%5Cfrac%7B1%7D%7B3%7D%28-3%20x%2B4%29%3D%5Cfrac%7B4%7D%7B3%7D)
Multiplying the term
by
, we get,
![-3 x+4-x+\frac{4}{3}=\frac{4}{3}](https://tex.z-dn.net/?f=-3%20x%2B4-x%2B%5Cfrac%7B4%7D%7B3%7D%3D%5Cfrac%7B4%7D%7B3%7D)
Subtracting both sides by
,
![-3x+4-x=0](https://tex.z-dn.net/?f=-3x%2B4-x%3D0)
Simplifying, we get,
![\begin{aligned}-4 x+4 &=0 \\-4 x &=-4 \\x &=1\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D-4%20x%2B4%20%26%3D0%20%5C%5C-4%20x%20%26%3D-4%20%5C%5Cx%20%26%3D1%5Cend%7Baligned%7D)
Now, substitute
in ![y=-3x+4](https://tex.z-dn.net/?f=y%3D-3x%2B4)
![y=-3(1)+4\\y=-3+4\\y=1](https://tex.z-dn.net/?f=y%3D-3%281%29%2B4%5C%5Cy%3D-3%2B4%5C%5Cy%3D1)
Thus, the solution is ![(1,1)](https://tex.z-dn.net/?f=%281%2C1%29)
A is the answere for your eqation to the problem
It's c, Meters because a kilometer is closer to a mile and a centimeter is closer to an inch
The y value in the table gets multiplied by 4 every time the x value goes up by 1. You can check your work using the values in the table given to you. 0.25 times four is 1. 1 times four is 4, and so on as the table goes.
The ratio would be written as 1:4