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Tpy6a [65]
3 years ago
5

H^2+14h=-31 Solve by completing the square

Mathematics
2 answers:
matrenka [14]3 years ago
5 0
Since the constant has been moved to the left side, you can move on to the next step which is adding (b/2)² to both sides of the equation.

h² + 14h + (14/2)² = -31 + (14/2)²

Simplify the parenthesis and exponent.

h² + 14h + 7² = -31 + 7²

h² + 14h + 49 = -31 + 49

h² + 14h + 49 = 18

Factor the expression of the left.

(h + 7)(h + 7) = 18

Take the square root of both sides.

√(h + 7)(h + 7) = ± √9 • 2

(h + 7) = ± 3√2

h + 7 = ± 3√2

Subtract 7 from both sides.

You solutions are:

h = -7 + 3√2 → -2.7573 → -2.76

h = -7 - 3√2 → -11.2426 → -11.24
ehidna [41]3 years ago
4 0
Given   <span>H^2+14h=-31, let's complete the square of the 1st two terms:

h^2 + 14h + (14/2)^2  =  -31 + (14/2)^2

  h^2 + 14h + 49   =   -31 + 49 = 18

   (h+7)^2 = 18

Taking the sqrt of both sides,

h+7 = sqrt (9*2) = 3 sqrt(2)

Solving for h,    h= -7 plus or minus 3 sqrt(2)    (answer)</span>
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Simplify each answer into a fraction, Please show work as well!
scoray [572]

Answer: 1) 8/15 2) 2 4/9 3) -13/45

Step-by-step explanation:

1/5 + 1/3 = 6/30 + 10/30 = 16/30 = 8/15

2 1/9 + 1/3 = 19/9 + 3/9 = 22/9 = 2 4/9

1/9 - 2/5 = 5/45 - 18/45 = -13/45

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2 years ago
I need the answers for these pls help
DanielleElmas [232]

Answer:

1)

A. m arc QRS = 100°

B. m arc QRT = 255°

C. m arc UTS = 180°

D. m arc UTR = 205°

2)

1] The major arc CA = 255°

2] The minor arc AB = 90°

Step-by-step explanation:

In a circle:

  • The measure of an central angle is equal to the measure of its subtended arc
  • The measure of a circle is 360°
  • Any chord divides a circle into two arcs, a minor arc its measure is < 180° and a major arc its measure is > 180°, the sum of the measures of the minor and major arcs is 360°
  • If the measures of the minor and major arcs are equal, then each arc represents a semi-circle

1)

In circle O

A.

∵ m∠QOR = 75°

∵ ∠QOR subtended by arc QR

- By using the 1st note above

∴ m of arc QR = m∠QOR

∴ m of arc QR = 75°

∵ m∠ROS = 25°

∵ ∠ROS subtended by arc RS

∴ m of arc RS = m∠ROS

∴ m of arc RS = 25°

The measure of arc QRS is the sum of the measures of arcs QR and RS

∴ m arc QRS = 75° + 25° = 100°

B.

∵ m∠SOT = 155°

∵ ∠SOT subtended by arc ST

∴ m of arc ST = m∠SOT

∴ m of arc ST = 155°

The measure of arc QRT is the sum of the measures of arcs QR, RS and ST

∴ m arc QRT = 75° + 25° + 155 °= 255°

C.

∵ m∠UOT = 25°

∵ ∠UOT subtended by arc UT

∴ m of arc UT = m∠UOT

∴ m of arc RUT = 25°

The measure of arc UTS is the sum of the measures of arcs UT and TS

∴ m arc UTS = 25° + 155° = 180°

D.

The measure of arc UTR is the sum of the measures of arcs UT, TS and SR

∴ m arc UTR = 25° + 155° + 25 = 205°

2)

1]

∵ The sum of the measures of the minor and major arcs is 360°

∵ m of minor arc AC = 105°

- Subtract 105 from 360° to find the measure of the major arc CA

∴ m of major arc CA = 360° - 105°

∴ m of major arc CA = 255°

2]

∵ m of major arc AB = 270°

- Subtract 270° from 360° to find the measure of the minor arc AB

∴ m of minor arc AB = 360° - 270°

∴ m of minor arc AB = 90°

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Answer:

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Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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Answer:

Prism

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D- A pyramid is not parallel.

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