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3 years ago

PLEASE HELP ME I NEED THIS REALLY BAD ALL MULT CHOICE PLEASE SHOW SOME WORK

Mathematics

2 answers:

aivan3 [116]3 years ago

6 0

b. 24.4. Using a squared + b squared = c squared you get 24.4

lyudmila [28]3 years ago

4 0

Pythagoras theorem a^2 + b^2 = c^2
Answer is B.

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SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS

antiseptic1488 [7]

Answer:

$\sf -11+7\sqrt{2}$

Step-by-step explanation:

Given expression:

$\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }$

Rewrite 32 as 16 · 2:

$\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }$

Apply radical rule $\sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }$

As $\sf \sqrt{16}=4$ :

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }$

Multiply by the conjugate:

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }$

$\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}$

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}$

As $\sf \sqrt{2}\sqrt{2}=\sqrt{4}=2$ :

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}$

$\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}$

$\sf \implies \dfrac{11-7\sqrt{2}}{-1}$

$\sf \implies -11+7\sqrt{2}$

7 0

2 years ago

What are the values of x ?

Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

since they are parallel then 2x+6=106

so subtract 6 from each side so it's 2x = 100

then divide each since by 2

so x= 50

7 0

2 years ago

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Simplify (7/9a+9/7b)^2-ab

lianna [129]

Ab+49/81a^2+81/49b^2

7 0

2 years ago

To finance her community college education, Sarah takes out a loan for $3400. After a year Sarah decides to pay off the interest

sdas [7]

She has to pay $170 i think

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3 years ago

Can anyone help with this

vesna_86 [32]

I would be able to but i left my maths book at school and that has the explanation in, sorry :(

8 0

3 years ago

Read 2 more answers