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Paha777 [63]
3 years ago
12

The temperature fell from 0 Degrees Fahrenheit to 15 and one-half Degrees Fahrenheit below 0 in 5 and three-fourths hours. Wen t

ried to find the change in temperature per hour. Her work is shown below.
Mathematics
2 answers:
Ksju [112]3 years ago
8 0

Answer:

Step-by-step explanation:

I don't see Wen's work, but I'll show you mine!

We can create a set of coordinates for each of these sets of data, where x is the time in hours, and y is the number of degrees in Fahrenheit.

At time 0, the temp is 0: (0, 0)

5.75 hours late, the temp is -15.5: (5.75, -15.5)

We can find the change in temp per hour by using the slope formula, since slope is, after all, the rate at which something is changing.

m=\frac{-15.5-0}{5.75-0}=\frac{-15.5}{5.75}=-2.7 That is rounded to the tenths place from -2.695652174 so you can round it however you need. What the interpretation of this number is is that temp is falling at a rate of 2.7 degrees F per hour.

Marina CMI [18]3 years ago
6 0

Answer:

- 2 16/23 degrees / hr

Step-by-step explanation:

15 1/2 = 31/2

5 3/4 = 23/4

31/2 ÷ 23/4 =

31/2 ×  4/23 =  124/46 = 62/23 = 2 16/23

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Step-by-step explanation:

What Is Cone Height Formula in Geometry? The cone height formula calculates the height of the cone. The height of the cone using cone height formulas are, h = 3V/πr 2 and h = √l2 - r2, where V = Volume of the cone, r = Radius of the cone, and l = Slant height of the cone.

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3 years ago
What is 300 divided by 7
miskamm [114]
42.857 is the answer to 300÷ 7
6 0
4 years ago
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Find the distance between the given points: (2, -2) and (-4, 7)
sasho [114]

Answer:

3\sqrt{13}

Step-by-step explanation:

Hi there!

We want to find the distance between the points (2, -2) and (-4, 7).

To do that, we can use the distance formula.

The distance formula is given as \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, where (x_1, y_1) and (x_2, y_2) are points

We have everything needed to find the distance, but let's label the values of the points to avoid any confusion

x_1=2\\y_1=-2\\x_2=-4\\y_2=7

Now substitute those values into the formula and solve

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\sqrt{(-4-2)^2+(7--2)^2}

Simplify

\sqrt{(-4-2)^2+(7+2)^2}

\sqrt{(-6)^2+(9)^2}

Square the numbers under the radical

\sqrt{36+81}

Add the numbers under the radical together

\sqrt{117}

Simplify the square root

3\sqrt{13}

Hope this helps!

6 0
3 years ago
Let f = {(x, y) ∈ R × R | xy = 2x + y + 1} There is at least one x ∈ R with no y ∈ R. Find all such problematic x ∈ R. Then rest
loris [4]

Answer:

Problematic x is x = 1

Step-by-step explanation:

Equation:

xy= 2x + y + 1

xy - y = 2x + 1

y(x-1) = 2x + 1

y = (2x+1)/(x-1)

The problematic x is such that when the denominator of the function is 0

x - 1 = 0

x = 1 (the problematic x)

So the domain of f is: x is the subset of R (real number) with the exception of x =/ 1 (x not equal to 1)

To prove this, we can plot the graph and in the graph we can see that as the value of x approaches from negative values to 1, y value will approaches negative infinity, and as the value of x approaches from large positive numbers, y value approaches infinity.

In other words, we'll see an assymptote at x=1

To prove that it is a function, we can do vertical line test by drawing vertical lines accross the graph. We'll see that each line crosses the equation line once hence proving the equation as a function

5 0
3 years ago
Using intervals of width 10, how many intervals
solniwko [45]

Answer:D

Step-by-step explanation:

4 0
3 years ago
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