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2 years ago

The graph of a function must be linear if it has what characteristic?

Mathematics

2 answers:

mario62 [17]2 years ago

3 0

The graph of a function must be linear if x is not squared in the function

kotykmax [81]2 years ago

3 0

Answer:

Slope of linear graph function will be constant.

Step-by-step explanation:

Linear function graph:The equation of linear graph function is given by

$f(x)=mx+b$

The degree of linear graph function is one.

Differentiate w.r.t x

Then, we get

$y'=m$

Slope of linear function is m.m is constant.

Therefore, if a graph is graph of linear function then it will have constant slope m.

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A number that can be represented as a decimal

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25 can be seen as .25

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Subtract this problem

galina1969 [7]

I think it's 1.90. I am not fully sure about the answer if it's wrong.

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2 years ago

If c= what is the value of a?

PilotLPTM [1.2K]

Answer:

a= 17√3/ 2 or a≈14.72

Step-by-step explanation:

c = 17 and is the side opposite to the angle C

c=AB =17

a= BC because is the side opposite to angle A

sin 60° = opp./hyp = BC / AB = BC/17

sin 60° = BC /17 multiply both sides by 17

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2 years ago

Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

stiv31 [10]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

5 0

2 years ago

Read 2 more answers

A health psychologist knew that corporate executives in general have an average score of 2.55 with a standard deviation of 0.5 o

Mumz [18]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Population mean (μ) = 2.55

Population standard deviation (σ) = 0.5

Sample size (n) = 30

Sample mean (x) = 2.76

α = 0.05

STEP 1:

Stress score in general executive (s1)

Stress score in exercising executive (s2)

Null : s1 = s2

Alternative : s1 < s2

STEP 2:

Shape of distribution = normal

Population mean (μ) = 2.55

Population standard deviation (σ) = 0.5

Sample size (n) = 30

Sample mean (x) = 2.76

α = 0.05

Decision rule :

α = 0.05 which corresponds to a t score (t0) ;

df = n - 1 = 30 - 1= 30 at 0.05 = 1.699

If :

(Test statistic (t) > t0) ; reject the Null

(right tailed test)

Test statistic (t) :

(x - μ) / (σ/√n)

(2.76 - 2.55) / (0.5/√30)

0.21 / 0.0913

= 2.30

t > t0

2.30 > 1.699

t is more extreme than t0

Hence, reject the null at α = 0.05

7 0

3 years ago