Answer:
(0,1)- y intercept (1,0) x intercept
Step-by-step explanation:
first lets write this equation in slope intercept form: y=mx+b
m=slope
b=y intercept
so
slope formula:
(y2-y1)/(x2-x1)
y2=-3
y1=9
x2=4
x1=-8
so
(-3-9)/(4--8)=-12/12=-1
slope=-1
hence
y=-1x+b
substitute "x" as 4 and "y" as -3
so
-3=-1(4)+b
-3=-4+b
1=b
so
y=-x+1
1=y intercept
and
0=-x+1
-1=-x
1=x
1=x intercept
To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
I believe it's C.
(Hint: y=mx+b)
M is Slope and B is Y-Intercept.
Answer:
6
Step-by-step explanation:
Perimeter = 2l + 2w
48 = 2(18) + 2(w)
48 = 36 + 2w
12 = 2w
w = 6
<em>Could you please give me brainliest for this? Thank you!</em>