Answers:
When we evaluate a logarithm, we are finding the exponent, or <u> power </u> x, that the <u> base </u> b, needs to be raised so that it equals the <u> argument </u> m. The power is also known as the exponent.

The value of b must be <u> positive </u> and not equal to <u> 1 </u>
The value of m must be <u> positive </u>
If 0 < m < 1, then x < 0
A <u> logarithmic </u> <u> equation </u> is an equation with a variable that includes one or more logarithms.
===============================================
Explanation:
Logarithms, or log for short, basically undo what exponents do.
When going from
to
, we have isolated the exponent.
More generally, we have
turn into 
When using the change of base formula, notice how

If b = 1, then log(b) = log(1) = 0, meaning we have a division by zero error. So this is why 
We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.
1) use distributive property
3x - 6 + 5x + 4
8x - 2
2) 4-2x - 14 - 3
-14 - 2x
Answer:
Slope is 1.5 and y-intercept is 11
Step-by-step explanation:
It's in the equation
The answer will be A. Hope it help!
Answer:
P(2U5) = 7/21 = 1/3
the probability of getting either a 5 or a 2 in one throw is 1/3
Step-by-step explanation:
Given that; the probability of each face turning up is proportional to the number of dots on that face
P(1) = 1×P(1)
P(2) = 2×P(1)
P(3) = 3×P(1)
P(4) = 4×P(1)
P(5) = 5×P(1)
P(6) = 6×P(1)
P(T) = 21×P(1)
Where;
P(x) is the probability of getting number x on the dice.
P(T) is the total probability of obtaining any number
N(x) is the number of possible number x in terms of the distribution function.
P(x) = N(x)/N(T) ....1
And since P(T) is constant, and P(T) is proportional to N(T) then,
P(x) is directly proportional to N(x)
So, equation 1 becomes;
P(x) = N(x)/N(T) = P(x)/P(T) ....2
The probability of getting either a 5 or a 2 in one throw
P(2U5) = (P(2) + P(5))/P(T)
Substituting the values of each probability;
P(2U5) = (2P(1) + 5P(1))/21P(1)
P(2U5) = 7P(1)/21P(1)
P(1) cancel out, to give;
P(2U5) = 7/21 = 1/3
the probability of getting either a 5 or a 2 in one throw is 1/3