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3 years ago

5

1.) A florist sells bouquets for $12.25 each. Amiyah

1 answer:

deff fn [24]3 years ago

6 0

Answer:

Step-by-step explanation:

J

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X=3 and y=(-2), find the value of 2x -- 3y

Leni [432]

2(3)-3(-2)=6-(-6)=6+6=12

4 0

3 years ago

Find the equation of the line through point (10,4) and parallel to 3x+5y=8.

Gnom [1K]

Parallel = same slope
Find slope of 3x + 5y = 8
Turn into y = mx + b
5y = -3x + 8
Divide by 5
y = -3/5x + 8/5
Slope is -3/5
Y = -3/5x + b, find y intercept
Plug in the point
4 = -3/5(10) + b
4 = -6 + b, b = 10
Final equation: y = -3/5x + 10

8 0

3 years ago

35 solve the following syste

blondinia [14]

Part A: The solution is $(-0.923,5.692)$

Part B: The point $(3,7)$ is not in the solution set.

Explanation:

Part A: The given inequalities are $3 x+4 y>20$ and $x$

The solution can be determined by solving the two inequalities by substitution method.

Changing inequalities to equality, we have,

$x=3 y-18$ and $3 x+4 y=20$

Let us substitute $x=3 y-18$ in the equation $3 x+4 y=20$ , we get,

$3 (3y-18)+4 y=20$

$9y-54+4y=20$

$13y=74$

$y=5.692$

Substituting $y=5.692$ in $x=3 y-18$ , we get,

$x=3 (5.692)-18$

$=17.076-18$

$x=-0.923$

Thus, the solution set is $(-0.923,5.692)$

Part B: Now, we shall determine whether the point $(3,7)$ is in the solution set.

Let us substitute the point $(3,7)$ in the inequalities $3 x+4 y>20$ and $x$ , we get,

$3 (3)+4 (7)>20$

$9+28>20$

$37>20$

Also, substituting $(3,7)$ in $x$ , we get,

$3$

$3$

$3$

Since, the point $(3,7)$ does not satisfy one of the inequality $x$ , the solution set does not contain the point $(3,7)$

Thus, the point $(3,7)$ is not in the solution set.

8 0

3 years ago

Someone answerrrrrr plssss ASAP!!!!!!’

ikadub [295]

Answer:

9. It seems he was inactive/taking a break, as the line is completely straight.

I'm not sure about the others, but I hope that helps!

Step-by-step explanation:

4 0

3 years ago

Which logarithmic graph can be used to approximate the value of y in the equation 4^y = 5?

Sloan [31]

$4^{y} = 5

log_{4}(4)^{y} = log_{4}(5)

y=log_{4}(5)

So, the graph of the function should be y=log_{4}(x), or f(x)= log_{4}(x)

Correct answer is the last one.$

3 0

3 years ago