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MrRissso [65]
3 years ago
7

Suppose a normal distribution has a mean of 16 and a standard deviation of 4.

Mathematics
2 answers:
olga55 [171]3 years ago
8 0

Answer:

Correct Answer is 2.5

Step-by-step explanation:

Lina20 [59]3 years ago
4 0
To calculate the number of standard deviations away from the mean, we first subtract the actual score from the mean, then divide the difference by the standard deviation. In this case, our actual score is 26, so we subtract from the mean of 16, then divide by the SD of 4
(26 - 16) / 4 = 2.5
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Given the vector equation ????(t)=(4−3t)????+(−5+t)????+(3−t)????, rewrite this in terms of the parametric equations for the lin
Anit [1.1K]

Answer:

The parametric equations for the line.x(t)=

y(t)=

z(t)=

is  

 \= r (t) =  \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}}  \atop {z(t)=3-t}} \right \}

Step-by-step explanation:

From the question we are told that

      the given equation is

                \= r(t) =  (4-3t) + (-5 + t) + (3-t)

This given equation can be represented as

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Generally this equation can be represented in terms of the parametric equations as follows

   \= r (t) =  \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}}  \atop {z(t)=3-t}} \right \}

This above equation is obtained by assigning each component of r(t) to each  line

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