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3 years ago

6

Angle measurements 110 degree help find out the balance at the top

1 answer:

ella [17]3 years ago

7 0

Answer: 70 degrees because 180-110= 70. Hope this helps

Step-by-step explanation:

You might be interested in

Enter the range of values for x

Pavlova-9 [17]

<em>Greetings from Brasil...</em>

See the attached figure. The smaller the θ angle, the smaller the AB side will be. If the angle θ = 90º, then AB = 25. As θ < 90, then AB < 25

5X - 10 < 25

5X < 25 + 10

X < 35/5

X < 7

The AB side can be neither zero nor negative. So

5X - 10 > 0

5X > 10

X > 10/5

X > 2

<h3>2 < X < 7</h3>

8 0

3 years ago

A shark swimming 14 feet below the surface of the water. It descends 15 feet to catch a fish and then ascends 8 feet. Describes

kompoz [17]

Answer:

22 FT

Step-by-step explanation:

14+15-8=22

8 0

3 years ago

What is the value of y

kari74 [83]

Answer:

y= -6

Step-by-step explanation:

-2y - 5y= -7y

-7y=42

42/-7=

y= -6

5 0

2 years ago

After mixing two types of candies, the price became $3.40 per lb. The quantity of the first type of candy was 5/12 of the quanti

drek231 [11]

Answer:

$2.90

Step-by-step explanation:

The quantity of the 1st type of candy be x lb and that of the second type − y lb with the price of $ p/lb.

Then, x=5y/12 or y=2.4x.

The "total price" equation will be: 4.6x + 2.4xp = 3.4(x+2.4x).

Solving for p, we get p = $2.90.

5 0

3 years ago

Can please someone help me? The question is in the picture. Thank you

maxonik [38]

Answer:

C. $9\pi$

Step-by-step explanation:

We proceed to solve for $x$ by the Pythagorean Theorem:

$(x+1)^{2} = (x-1)^{2} + (2\cdot x - 4)^{2}$ (1)

$x^{2} + 2\cdot x + 1 = (x^{2}-2\cdot x + 1) + (4\cdot x^{2}-16\cdot x + 16)$

$x^{2} + 2\cdot x + 1 = 5\cdot x^{2}-18\cdot x + 17$

$4\cdot x^{2} -20\cdot x + 16 = 0$

$(2\cdot x)^{2} -10\cdot (2\cdot x) + 16 = 0$

$(2\cdot x -8)\cdot (2\cdot x -2) = 0$

There are two different solutions:

$x_{1} = 4$ , $x_{2} = 1$

A solution of $x$ is considered realistic when the length of every side of the triangle is a not negative number.

$x_{1} = 4$

$UV = 2\cdot (4) - 4$

$UV = 4$

$WU = 4 - 1$

$WU = 3$

$WV = 4 + 1$

$WV = 5$

$x_{2} = 1$

$UV = 2\cdot (1) - 4$

$UV = -2$

$WU = 1 - 1$

$WU = 0$

$WV = 1 + 1$

$WV = 2$

The only realistic set of solutions is for $x = 4$ , and the radius of the circle is represented by the line segment $WU$ : $r = 3$

And the area of the circle ( $A$ ) is calculated from the following formula:

$A = \pi\cdot r^{2}$

$A = \pi\cdot (9)$

$A = 9\pi$

The correct answer is C.

6 0

3 years ago