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seropon [69]
2 years ago
12

Can you help me with these problems and explain step by step Cuz i have no clue how to do them

Mathematics
1 answer:
yuradex [85]2 years ago
5 0
I know how to do it but I don’t know how to simply explain it on here without confusing myself but first you have to graph the points
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Find the percent of change. Original: 80, new: 64
lara31 [8.8K]
Hi there!

To find the percent of change we can use the following formula:
\frac{new - old}{old} \times 100\%

Let's fill in our data
\frac{64 - 80}{80} \times 100\% =

Subtract
\frac{ - 16}{80} \times 100\% =

Divide
- 0.2 \times 100\%

And finally multiply
- 20\%

Hence, the percent of change is negative 20%.
~ Hope this helps you!
3 0
3 years ago
Please answer question with work ♥️
vova2212 [387]

Answer:

r=201

d = 77 1/2

Step-by-step explanation:

6) First multiply left and right by 16, to get rid of the fraction:

r - 25 = 11*16

Now add 25 left and right:

r = 11*16 + 25 = 201


7) Add 5 left and right

2/5 d = 31

multiply by 5/2

d = 31 * 5/2 = 77 1/2

3 0
3 years ago
Solve this quadratic equation by completing the square. x2 + 10x = 26
Misha Larkins [42]
                        x² + 10x = 26
                x² + 10x + 25 = 26 + 25
          x² + 5x + 5x + 25 = 51
x(x) + x(5) + 5(x) + 5(5) = 51
         x(x + 5) + 5(x + 5) = 51
                 (x + 5)(x + 5) = 51
                          (x + 5)² = 51
                             x + 5 = ±√(51)
                                 - 5      - 5
                                   x = -5 ± √(51)
                                   x = -5 + √(51)    or    x = -5 - √(51)
5 0
3 years ago
Read 2 more answers
I need help, please​
tensa zangetsu [6.8K]

Answer:

C

Step-by-step explanation:

12^2 = 144, 9^2 = 81, and 15^2 = 225.

144 + 81 = 225, therefore a^2 + b^2 = c^2.

4 0
2 years ago
Read 2 more answers
A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 86m long and 62m wide.
-Dominant- [34]
The area of the rectangle is 5,332.
6 0
3 years ago
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