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3 years ago

8

During a solar eclipse, what is causing the earth’s view of the sun to be darkened?

2 answers:

Darina [25.2K]3 years ago

8 0

A solar eclipse occurs when the moon gets between Earth and the sun, and the moon casts a shadow over Earth. A solar eclipse can only take place at the phase of new moon, when the moon passes directly between the sun and Earth and its shadows fall upon Earth's surface.

Serggg [28]3 years ago

7 0

Answer:

the moon blocks light from the sun by coming between the earth and the sun

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Solve the equation.

blondinia [14]

Answer: 12

Step-by-step explanation:

6c + 11= 2c + 59

Collect like terms

6c - 2c = 59 - 11

4c = 48

c = 48/4

c = 12

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Form the greatest and the smallest 4-digit number using the following digits

MrMuchimi

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A ball moves in a straight line has an acceleration of a(t) = 2t + 5. Find the position function of the ball if its initial velo

Vlad1618 [11]

Answer:

$s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12$

Step-by-step explanation:

Relation between acceleration, velocity and position:

The velocity function is the integral of the acceleration function.

The position function is the integral of the velocity function.

Acceleration:

As given by the problem, the acceleration function is $a(t) = 2t + 5$

Velocity:

$v(t) = \int a(t) dt = \int (2t+5) dt = \frac{2t^2}{2} + 5t + K = t^2 + 5t + K$

In which K is the constant of integration, which is the initial velocity. So K = -3 and:

$v(t) = t^2 + 5t - 3$

Position:

$s(t) = \int v(t) dt = \int (t^2 + 5t - 3) = \frac{t^3}{3} + \frac{5t^2}{2} - 3t + K$

In which K, the constant of integration, is the initial position. Since it is 12:

$s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12$

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3 years ago

Select the expression that is equivalent to 48 + 12.

Natalija [7]

Answer to your question : 12(4+1)

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3 years ago