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3 years ago

8

Jill uses summer for honey to make lotion if each bottle of lotion requires 1/4 gallon and she uses a total of 3 gallons how man

y bottles of lotion does she make

1 answer:

Paul [167]3 years ago

4 0

Answer:

12 Bottles of Lotion

Step-by-step explanation:

If Each bottle uses 1/4 Gallon (0.25 Gallon) then in order to find how many bottles of lotion Jill will be able to make with 3 Gallons, you would need to divide the 3 Gallons by the amount each bottle needs, like so...

3 gallons / 0.25 = # of Bottles

3 gallons / 0.25 = 12 Bottles

After doing this small calculation we can see that from the 3 Gallons Jill will be able to make a total of 12 Bottles of Lotion

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The sum of two numbers is equal to 70. Which of the following functions can be use to find the product of the two numbers if one

Temka [501]

Let x=number 1 let y=number2
there sum is equal to 70
then

number1+number2=70

substituting

x+y=70

y=70-x
let there product will be p
p=xy
substituting
p=x(70-x)
which is choice c

4 0

3 years ago

Point K is on line segment JL. Given JK = 2x – 2, KL

Scorpion4ik [409]

Answer:

KL = 10

Step-by-step explanation:

JK + KL = JL

2x – 2 + x – 9 = 2x + 8

Combine like terms

3x -11 = 2x+8

Subtract 2x from each side

3x-2x -11 = 2x+8-2x

x-11 = 8

Add 11 to each side

x-11+11 = 8+11

x = 19

KL = x – 9

= 19-9

= 10

8 0

3 years ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

(-10p+9=12) I need somebody to solve this and show me the work of this equation.

Misha Larkins [42]

-10p+9=12
-9 -9
-10p=3
—— —
-10 -10
P=3/-10 or -0.3

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3 years ago

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Answer:

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2 years ago