Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
-x + 10
Step-by-step explanation:
(x + 7) - (2x-3)
x + 7 - 2x - 3
x - 2x
-x + 7 + 3
-x + 10
Answer:
jhvghvhgvvvvvvvvvvvvvvvvvvvv
Step-by-step explanation:
Answer:
I dont see the picture sry
Answer:
-19
Step-by-step explanation:
3x+2 = -55
-2 -2
3x = -55-2
3x = -55+-2
3x = -57
/3 /3
x=-19