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mylen [45]
3 years ago
13

a baker orders 162 eggs. each carton contains 18 eggs. which equation can you use to find the number x of cartons? explain your

reasoning and sold the equation.
Mathematics
2 answers:
svetlana [45]3 years ago
8 0
This is just dividing 
So the baker orders 162 eggs and each carton has 18 eggs 
so 162 ÷ 18 = 9 cartons 
And if you want to check if its correct 
9 x 18 = 162 eggs
ololo11 [35]3 years ago
6 0
18x = 162
Divide 162 by 18 and x equals  9 
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4 0
4 years ago
As – 16a,<br> as – 4a3,<br> 2a3 + 8a - 4a2 - 16
vfiekz [6]

Answer:

1) as-16a

taknig a as common

=a(s-16)

2)as-4a³

taking a as common

=a(s-4a²)

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taking common terms

=2a(a²+4)-4(a²+4)

=(2a-4)(a²+4)

again taking common

=2(a-2)(a²+4)

i hope this will help you :)

7 0
3 years ago
Paula and Kawai shared $312 in the ratio of 6:7. How much money<br> did each person get?
Maslowich

Answer:

Paula get \$144 and Kawai get \$168.

Step-by-step explanation:

Given: Paula and Kawai shared \$312 in the ratio of 6:7.

To find: How much money  did each person get?

Solution:

We have,

Paula and Kawai shared \$312 in the ratio of 6:7.

So, let Paula get \$6x and Kawai get \$7x.

As per the question,

6x+7x=312

\implies13x=312

\implies x=\frac{312}{13} =24

Therefore, Paula get 6\times 24=\$144, and Kawai get 7\times 24=\$168.

Hence, Paula get \$144 and Kawai get \$168.

6 0
3 years ago
Write an equation in slope-intercept form with the given slope and y-intercept.
sleet_krkn [62]

Answer: slope: 3/2

y-intercept: 0,4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
IQ scores based on the​ Stanford-Binet IQ test are normally distributed with a mean of 100 and standard deviation 15. If you wer
lianna [129]

Answer:

95 intervals

Step-by-step explanation:

Given that

population mean = 100

standard deviation = 15

number of interval that involve the mean for 95% confidence interval is calculated as

We know that when we measure the 99 percent confidence interval, 99 outof 100 confidence interval are required to provide the mean population.

similarly

Assuming we measure a confidence interval of 95 percent, then we  should expect 95 out of 100 confidence interval to provide the mean population therefore, answer is 95

7 0
3 years ago
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