All categories

3 years ago

Tina observes the points on the plane of a paper. What is the minimum number of points required to make a plane?

Mathematics

1 answer:

Ymorist [56]3 years ago

3 0

Isnt it 3? because hes making a plane

You might be interested in

A shipment of 105 Otter box covers for I-phones has arrived. The total invoice (excluding tax, shipping, etc.) is $3,849.75.

bezimeni [28]

3,849.75 ÷ 49.95 = 77 (Calculator)

Sense you would like it explained than the question is asking how many otter box Defender Covers where shipped in that price. So when you have that they want the amount of Otter Box Defenders than you divide the amount paid for the shipment with the amount of the otter box defender price.

I hope this is helpful.

3 0

3 years ago

Simplify x^2-9/x^2+x-12

vagabundo [1.1K]

Answer:

I love algebra anyways

the ans is in the picture with the steps

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

3 0

2 years ago

The price of a game thats been discounted 18% off its price(x)?

vlada-n [284]

0.0018 is what is was in a decimail but i dont know what the quiestion is

4 0

2 years ago

Plsss help i get a f plus in math

Lemur [1.5K]

Answer:

C. 1.5

Step-by-step explanation:

7 0

2 years ago

If N is the population of the colony and t is the time in days, express N as a function of t. Consider Upper N 0 is the origina

lesya [120]

Answer:

(a) $N(t)=Noe^{kt}$

(b)5,832 Mosquitoes

Step-by-step explanation:

(a)Given an original amount $N_o$ at t=0. The population of the colony with a growth rate $k \neq 0$ , where k is a constant is given as:

$N(t)=Noe^{kt}$

(b)If $N_o=1000$ and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

$1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)$

Therefore, our model is:

$N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t$

In 3 days time

$N(3)=1000\cdot1.8^3=5832$

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

$N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days$

In approximately 5 days, the population of mosquitoes will be 20,000.

7 0

2 years ago

Read 2 more answers