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GaryK [48]
3 years ago
9

What is X and A??? The have to equal the same thing, but one is multiplying and one is adding (picture)

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0
X*a = 244  is equation (1)
x+a = 2    is equation (2)

Solve equation (2) for 'a' to get
x+a = 2
a = 2-x
Call this equation (3)

We will plug equation (3) into equation (1)
x*a = 244
x*(a) = 244
x*(2-x) = 244
Notice how the 'a' is replaced with an expression in terms of x

Let's solve for x
x*(2-x) = 244
2x-x^2 = 244
x^2-2x+244 = 0

If we use the discriminant formula, d = b^2 - 4ac, then we find that...
d = b^2 - 4ac
d = (-2)^2 - 4*1*244
d = -972
indicating that there are no real number solutions to the equation x^2-2x+244 = 0

So this means that 'x' and 'a' in those two original equations are non real numbers. If you haven't learned about complex numbers yet, then the answer is simply "no solution". At this point you would stop here. 

If you have learned about complex numbers, then the solution set is approximately 
{x = 1 + 15.588i, a = 1 - 15.588i}
which can be found through the quadratic formula

Note: it's possible that there's a typo somewhere in the problem that your teacher gave you. 

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Suppose a die is tossed 5 times. what is the probability of getting exactly 2 fours?
Tasya [4]

Answer:

the probability of getting exactly 2 fours is 0.16

Step-by-step explanation:

The probability of obtaining a number that is four = ¹/₆

The probability of obtaining a non 4 number = 1 - ¹/₆ = ⁵/₆

The number of ways 2 fours can be arrange in five numbers = ⁵C₂ = 10 ways

If the die is tossed five times, the probability of the events is calculated as;

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3 years ago
What are the possible values of x in x2 + 3x + 3 = 0?
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Answer:

Step-by-step explanation:

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Are the lines 2y-10x=4 and y-2=5x parallel ??
aleksandrvk [35]
Well,

If the slope of the lines are the same, then the lines are parralel.

We need to manipulate 2y - 10x = 4 into y = mx + b form.

Add 10x to both sides
2y = 10x + 4

Divide both sides by 2
y = 5x + 2

Do the same thing with the other equation.

Add 2 to both sides
y = 5x + 2

y = 5x + 2

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Answer:

x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}

Second equation:

\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}

Third equation:

\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}

Now we use this value for "x" back in equation 1 to solve for "y":

1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}

And finally we solve for the third unknown "z":

\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12

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