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olga nikolaevna [1]
3 years ago
5

ty rode his trail bike for 4.5 hours. his average speed was 12 miles per hour. how many miles did he ride?

Mathematics
2 answers:
Viefleur [7K]3 years ago
5 0
Hey there!


Ty rode is bike 54 miles.

Work:
4.5 x 12


Hope this helps!
Ksenya-84 [330]3 years ago
3 0
The equation for this is 4.5 * 12.
4.5 * 12 = 48
The answer is 48.
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1.6 × 1.6 × 1.6 × 1.6 = 6.5536

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3 years ago
Solve for x,<br> m-3x=2x+p
just olya [345]
<span>m-3x=2x+p
m-x=p (- 2x on both sides)
-x=p-m (- m on both sides)
answer: x=-p+m (divide -1 on both side)

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3 years ago
How to solve it in quadratic functions
natita [175]

Answer:

x = 2

x = -3/2 or -1.5

Step-by-step explanation:

For this, I would use the "slip and slide" method. LOL I know the name is cheesy, but that's what my teacher called it!

First, you "slip" the coefficent of the leading term (2) to the constant, and multiply.

The equation becomes:

x² - x - 6(2) = 0

x² - x - 12 = 0

Then, you factor this out by looking at the second and third terms. You're looking for 2 factors of -12 that would add up to -1 ( the coefficent of the second term).

Automatically, think of 3 and 4, because the difference between them is 1.

The factors must be (x-4) and (x+3) because they multiple to -12, and add up to -1.

This step is extremely important! Lol I used to forget it a lot, but make sure you divide the constant in each factor by the original number you "slipped".

It would become (x-(4/2))(x+3/2) = (x-2)(x+3/2)

With (x+3/2), you don't want to leave it as a fraction or decimal. It's equivalent to (2x+3). However, the informal form is easier to identify the value of x.

6 0
3 years ago
What is the intial value and rate of change in this graph. please explain step by step!!!!!
WARRIOR [948]

The initial value of the graph is where x = 0. Thus, in this case, the initial value is 12.


The rate of change of the graph is essentially the slope of the graph. In this case, we can use the slope formula:

\dfrac{y_2 - y_1}{x_2 - x_1}

  • (x_1, y_1) and (x_2, y_2) are points on the graph

Let's use two points from the chart to find the slope:

m = \dfrac{30 - 21}{2 - 1} = 9


In this case, the rate of change of the graph is 9.

4 0
3 years ago
Read 2 more answers
Simplify each expression. Assume that all variables are positive.
kozerog [31]
Q1. The answer is  \frac{8x^{3}y^{6}  }{27}

( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} } \\  \\ &#10;  \frac{ x^{a} }{ x^{b} }= x^{a-b}  \\  \\ &#10;( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\  \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=
\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\  \\ &#10; (x^{a} )^{b} = x^{a*b}  \\  \\ &#10;\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } =  \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} = 
= \frac{8x^{3}y^{6}  }{27}

Q2. The answer is 1/16

(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} =  \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\  \\  (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } }  \\  \\ &#10;
\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } =  \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}


Q3. The answer is a^{ \frac{7}{6} }

a^{ \frac{2}{3} } * a^{ \frac{1}{2} }  \\  \\ &#10; x^{a}* x^{b}  =x^{a+b}  \\  \\ &#10;a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }
7 0
3 years ago
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