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The equation has one extraneous solution which is n ≈ 2.38450287.
Given that,
The equation;
We have to find,
How many extraneous solutions does the equation?
According to the question,
An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.
To solve the equation cross multiplication process is applied following all the steps given below.
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y
with 0 and solve for x. The graph of the equation is attached.
n ≈ 2.38450287
Hence, The equation has one extraneous solution which is n ≈ 2.38450287
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Answer:
(x,y) = (2,3)
Step-by-step explanation:
y=5x-7 (i)
-3x-2y= -12
-(3x+2y)= -12
3x+2y= 12 (ii)
By putting the value of y from (i) in (ii)
3x+2(5x-7)=12
3x+10x-14=12
13x=12+14
13x= 26
x =
x= 2
By putting the value of x in (i)
y= 5(2)-7
y= 10-7
y= 3
(x,y) = (2,3)