Let
be the dimensions of the rectangle. We know the equations for both area and perimeter:


So, we have the following system:

From the second equation, we can deduce

Plug this in the first equation to get

Refactor as

And solve with the usual quadratic formula to get

Both solutions are feasible, because they're both positive.
If we chose the positive solution, we have

If we choose the negative solution, we have

So, we're just swapping the role of
and
. The two dimensions of the rectangle are
and 
Using the Punnette Square :
R r
<span>R RR Rr </span>
<span>r Rr rr
</span>Hence,
<span>By applying the rules of probability Rr x Rr, the probability of the offspring being homozygous recessive will be one fourth or a quarter.
SO the best is :
B. 1/4</span>
Answer: The correct option is (A) reduction.
Step-by-step explanation: Given that the quadrilateral A'B'C'D' is a dilation of the quadrilateral ABCD.
As shown in the given figure, the lengths of the sides of quadrilateral ABCD are as follows:
AB = 5 units, BC = 4 units, CD = 10 units and DA = 6 units.
And, the lengths of the sides of quadrilateral A'B'C'D' are as follows:

We know that the dilation will be an enlargement if the scale factor is greater than 1 and it will be a reduction if the scale factor is less than 1.
Now, the scale factor is given by

Since the scale factor is less than 1, so the dilation will be a reduction.
Answer:
The Answer is 0,133484. The same number as
or
Step-by-step explanation:
If the probability of an event occurring is <em>p</em>, then the probability of an event not occurring is <em>1-p</em>. Therefore if Lester plays one number, then the probability of that number not winning is 1-
or 1-0.25, which is
or 0.75
Two or more events are independent if the occurrence of one does not affect the probability of occurrence of the other. In Lester's game, the probability of a number winning or not winning does not affect the probability of the same number winning or not winning in the next game.
In order to find the probability of several events occurring in succession, we multiply the probabilities of the individual events.
Therefore if Lester plays one number seven times, the probability that all seven bets lose are
or
Answer:
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