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Umnica [9.8K]
2 years ago
8

Graph and label each figure and it’s image under the given translation. Give the coordinates of the image.

Mathematics
1 answer:
lutik1710 [3]2 years ago
5 0

Answer:

See below ~

Step-by-step explanation:

<u>Question 3 : (x, y - 5)</u>

  • K' = (-3, 2 - 5) = <u>(-3, -3)</u>
  • L' = (1, 4 - 5) = <u>(1, -1)</u>
  • M' = (-1, 0 - 5) = <u>(-1, -5)</u>
  • N' = (-5, -2 - 5) = <u>(-5, -7)</u>

<u></u>

<u>Question 4 : (x + 4, y + 1)</u>

  • D' = (-4 + 4, 3 + 1) = <u>(0, 4)</u>
  • E' = (0 + 4, 2 + 1) = <u>(4, 3)</u>
  • F' = (-2 + 4, -6 + 1) = <u>(2, -5)</u>
  • G' = (-6 + 4, -5 + 1) = <u>(-2, -4)</u>
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Answer: This would fill 4 and 4/9 containers.

Explanation:

Since we have given that

Quantity of walnuts in a container is given by

6\frac{2}{3}=\frac{20}{3}\ pounds

Quantity of walnuts which divided equally into containers is given by

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Now, number of containers they would fill is given by

\frac{\frac{20}{3}}{\frac{3}{2}}=\frac{20\times 2}{3\times 3}=\frac{40}{9}

When we change it into mixed fractions we get,

\frac{40}{9}=4\frac{4}{9}

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Answer:

28

Step-by-step explanation:

n can be represented as 1.

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Please visit my church's website at fbcinterlaken.org to learn more about God. Please subscribe to the You Tube channel because my church really needs the support right now. Thank you! And have a nice day! :) (I will take brainliest).

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Nonlinear Systems of Equations
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The square root and cube root identities are proved.

According to the statement

we have to find that the use of the square root identity (x − y)2 = x2 − 2xy + y2

And use of cube root identity a3 + b3 = (a + b)(a2 − ab + b2).

So, For this purpose, we know that the

A. Let us assume the two conditions.

So,

2x + 3y = 6  -(1)

4x + 7y = 8  -(2)

Here we use elimination method

So, Multiply 4 with (1) and 2 with (2)

8x + 12y = 24  

8x + 14y = 16  

Now eliminate x from these equations

-2y = 8

here y is -4.

and the x become

2x + 3y = 6  

2x -12 = 6

2x = 18

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B. For the use of identity (x- y)^{2}  = x^{2} - 2xy + y^{2}

Let us assume a number 26 and 28 then fill it in the condition then

(28- 26)^{2}  = 28^{2} - 2(28)(26) + 26^{2}

Then

(28- 26)^{2}  = 784 - 1456 + 676

(28- 26)^{2}  = 4

And we have to prove the cube root identity then

The identity is

a^{3}  + b^{3}  = (a + b)(a^{2} - ab + b^{2})

Then let us assume the number 8 and 9 then

a^{3}  + b^{3}  = (a + b)(a^{2} - ab + b^{2})

8^{3}  + 9^{3}  = (8 + 9)(8^{2} - 8*9 + 9^{2})

8^{3}  + 9^{3}  = (17)(64 - 72 + 81)

8^{3}  + 9^{3}  = (17)(73)

8^{3}  + 9^{3}  = (1241)

Hence by this way we prove the square and cube root identities.

So, The square root and cube root identities are proved.

Learn more about square root and cube root here

brainly.com/question/661780

#SPJ1

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