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2 years ago

Graph and label each figure and it’s image under the given translation. Give the coordinates of the image.

Mathematics

1 answer:

lutik1710 [3]2 years ago

5 0

Answer:

See below ~

Step-by-step explanation:

Question 3 : (x, y - 5)

K' = (-3, 2 - 5) = (-3, -3)
L' = (1, 4 - 5) = (1, -1)
M' = (-1, 0 - 5) = (-1, -5)
N' = (-5, -2 - 5) = (-5, -7)

Question 4 : (x + 4, y + 1)

D' = (-4 + 4, 3 + 1) = (0, 4)
E' = (0 + 4, 2 + 1) = (4, 3)
F' = (-2 + 4, -6 + 1) = (2, -5)
G' = (-6 + 4, -5 + 1) = (-2, -4)

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Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd

mestny [16]

Answer:

1) $P(X = 8) = 0.1033$

$P(X = 9) = 0.0688$

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So $\mu = 6$ .

P(X = 8)

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033$

P(X = 9)

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688$

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

$E(X) = 200*0.1033 = 20.66$

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

$E(X) = 200*0.0688 = 13.76$

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3 years ago

Find line tangent to y=xcosx at point (pi, -pi)

slamgirl [31]

1) slope of the line = derivative of the of the function at the given point.

y' = cosx - x cosx

Evaluate for x = pi => y' = cos(pi) - pi*cos(pi) = -1 - (pi*cos(pi)) = -1 + pi

Then slope = -1 + pi

Given point: (pi, -pi)

Equation:

y - (-pi) = [-1+ pi] (x - pi)

y + pi = -x +pi + xpi -pi^2

y = (pi-1)x - pi^2 .... this is the answer

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3 years ago

How Can you represent writing a check for $10 as an integer? A b c or d

Lynna [10]

The answer to represent a check for 10$ is A. -10

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4 years ago

Sheldon harvests the strawberries and tomatoes in his garden.

shtirl [24]

Answer:

A. 3 13/20

B.3.8 kg

C.Strawberries

Step-by-step explanation:

In order to solve this we just need to find the amount of strawberries he picked, and if he picked 1 2/5 less in the morning and in the morning he picked 2 1/4, we just add that up to know how much he picked in the afternoon:

$1\frac{2}{5}+ 2\frac{1}{4}\\1 \frac{2(4)}{20}+ 2\frac{1(5)}{20}\\1 \frac{8}{20}+ 2\frac{5}{20}\\\\3\frac{13}{20}$

So in the afternoon he picked $3\frac{13}{20}$ .

Now he picked 5 3/10 kg of tomatoes but 1.5 were rotten, we just have to withdraw the rotten from the total:

$5\frac{3}{10} -1\frac{1}{2} \\5\frac{3}{10} -1\frac{5}{10} \\4\frac{3-5}{10} \\3\frac{13-5}{10} \\3\frac{8}{10}$

So now we know that he picked $3\frac{8}{10}$ kg of good tomatoes.

If he picked in the afternoon and the morning 5.05 kg of strawberries, he picked more strawberries than tomatoes.

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3 years ago

The sum of the exterior angles of a pentagon equals 360°.

Zolol [24]

True.

sum of exterior angles of a pentagon equals 360°

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3 years ago