Answer:
I believe both are 80 or 40
Step-by-step explanation:
The answer is three. divide 48 by any number under 6 if there a decimal they don't count if there answer is over 20 it doesn't count
Answer:
0.14 lb . . . closest choice is 0.11 lb
Step-by-step explanation:
The inside and outside radii are 1/8 in and 3/8 in, respectively. Then the area of the top of the washer is ...
A = π(R² -r²) = π((3/8)² -(1/8)²) = π(9/64 -1/64) = π/8 . . . square inches
The height of the stack of 5 washers will be 5×(1/4 in) = 5/4 in. So, the volume of material in the stack of washers is ...
V = Bh = (π/8)(5/4) = 5π/32 . . . cubic inches
The weight of material is the product of volume and density, so is ...
W = (5π/32 in³)(0.285 lb/in³) ≈ 0.1399 lb ≈ 0.14 lb
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<em>Comment on the question</em>
Since this answer does not correspond to any of the offered choices, we suggest you ask your teacher to work this out for you. We suspect they will have difficulty justifying any of the answer choices shown here. (0.11 lb corresponds to 4 washers, not 5.)
Use point (-3,2):
2 = 4*(-3) + b
b = 2 +12
b = 14
The equation is y = 4x + 14
Step-by-step explanation:
Answer:
140
Step-by-step explanation:
To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.
First, let's count the number of subsets that contain the element 3.
Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is
.
Now, let's count the number of subsets that contain the element 4.
4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in
ways.
We conclude that there are 70+70=140 required subsets of S.