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Veseljchak [2.6K]
3 years ago
6

PLEASE HELP ASAP Evaluate ƒ(x) when x = 6. 9 37 109 6

Mathematics
1 answer:
sergey [27]3 years ago
8 0

f(x) = 6 * 9 = 54        f(x)=54

f(x) = 6*37=222        f(x)=222

f(x)=6*109=654        f(x)=654

f(x)=6*6=36              f(x)=36

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Answer: -1/5

Step-by-step explanation:

14/20 - 81/90=

7/10-9/10=       ==> 10 is the GCF of 20 and 90

(7-9)/10=

-2/10=-1/5

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To fill the sandbox, she would need 15 cubic feet.

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To find the volume of a box, multiply all of its dimensions together.

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So, since she bought 20 cubic feet of sand, she should have enough with 5 cubic feet left over.

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6 0
3 years ago
A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

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P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

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0.0082 = 0.82% probability that he will pass

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Answer:

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