Question

Find the stationary points on the curve y = (3x – 1)(x - 2)^4.

Answer 1

Step-by-step explanation:

by using y=uv derivative formula and stationary mean y' = 0

y' = 3(x–2)⁴ + 3(3x–1)(x–2)³ = 0

cancel 3 and factorize

(x–2+3x–1)(x–2)³ = 0

x = ¾ or x = 2

we got point $\left(\frac{3}{4},\frac{5^5}{4^5}\right)$ and (2,0)