What is angle A in the following equation?

1 Given the functions f(x) and g(x) = find the following. 1 + x2 (a) (gºf)(x) 1 (b) (gºf)(6)

trapecia [35]

Okie so I can see you tomorrow and I’ll be right there on time to meet

8 0

3 years ago

Mrs. Bendit’s 1st Block class has 28 students. There are 7 girls in the class. What percent of boys are in the class?

Gemiola [76]

Answer:

Boys: 75%

Girls: 25%

Step-by-step explanation:

Total: 28 Students: 100%

7 Girls in clas

28(total)-7 (girls)= 21 Boys in class

__________________

If we divide the amount boys OR girls ( depending on which gender) after the toal and move the decimal to the right twice after dividing) we will get our answer.

Formula:

(Amount of Boy or girls) = x

X/28

So since we are trying to get the percentages of boys, we will replace X with the amount of boys

21/28 = .75 ( then move the decimal to the right TWICE) = 75

Then you should get your percentages: 75% Also if your lookings for girls percentages, you basically subtract 75 ( boys percentages) with the total percentages ( 100) then you should get your answer for the girls: 25%

7 0

2 years ago

Read 2 more answers

Given k(x) =x^3-2x, find k (3)

nadezda [96]

Answer: 21

Step-by-step explanation:

k(x) =x^3-2x

k(3) =3^3-2*(3)

k(3) =27-6

k(3) = 21

5 0

3 years ago

Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .