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Alona [7]
3 years ago
13

Two friends argue about the calculated probability of flipping a coin to show heads three times in a row. steve mentions that ea

ch flip is unconnected to the previous flip. this is an example of events that are what?
Mathematics
1 answer:
den301095 [7]3 years ago
4 0

Solution:

A coin is flipped three times,resulting three heads in a row.

Since Steve has mentioned that ,  each flip  of a coin is unconnected to the previous flip.

Two or more events are said to be independent if occurrence of one of them is not affected by the Occurrence of other.

This is an example of independent events.

In terms of probability, P (A∩B∩C)= P(A)×P(B)×P(C)

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If the scale factor is 5/3 what is the width of the new rectangle?
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Answer:

If 24 is the width then the answer is 40 and if 30 is the width then the answer is 50

Step-by-step explanation:

We multiply both sides by the scale factor to find both sides of the new rectangle. 30 * 5/3 = 50 and 24 * 5/3 = 40, so the sides of the new rectangle are 50 and 40. It matters whether 24 or 30 are the length or width, but if 24 is the width then the answer is 40 and if 30 is the width then the answer is 50

7 0
2 years ago
X²+x=0<br> x³-25x=0<br> x²=4x<br> 4x²-4x=1
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Answer:

x²+ x = 0

x ( x +1 ) = 0

x = -1

x³-25x=0

x ( x² - 25 ) = 0

x² = 25

x = 5

x²=4x

x² - 4x = 0

x ( x- 4 ) = 0

x = 4

4x²-4x=1

4x²-4x - 1 = 0

4 x² - 2x - 2x - 1 = 0

2x ( 2x - 1 ) - 1 ( 2x- 1 ) = 0

2x- 1 ) ² = 0

2x = 1

x = 1/ 2

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Dylan is wrapping a birthday present for his sister. The box the gift is in has a length of 6 inches, a width of 5 inches, and a
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24 in x 25 in


Or

24 in by 25 in
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3 years ago
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Explain how System 1 becomes equivalent to System 2.
Nostrana [21]

Answer:

\left\{\begin{array}{ccc}(A+L)x+(B+M)y=C+N\\Ax+By=C\end{array}\right

<h3>A.The first equation in System 2 is the sum of the equations in System 1. The second equation in System 2 is the first equation in System 1.</h3>

Step-by-step explanation:

\underline{+\left\{\begin{array}{ccc}Ax+By=C\\Lx+My=N\end{array}\right}\qquad\text{add both sides of the equations}\\(Ax+Lx)+(By+My)=C+N\qquad\text{distributive}\\(A+L)x+(B+M)y=C+N

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3 years ago
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