Given :
The average acceleration of a tennis ball that has an initial velocity of 6.0 m/s.
and a final velocity of 7.3 m/s.
It is in contact with a tennis racket for 0.094 s
To Find :
The average acceleration of the tennis ball.
Solution :
We know, average acceleration is given by :

Therefore, average velocity is given by 13.83 m/s².
Hence, this is the required solution.
Answer:
4.4×10⁻⁷ Coulomb
Explanation:
V = Voltage = 5.8 kV
d = Potential distance = 2.8 mm = 0.0028 m
A = Area = 0.3×0.08 = 0.024 m²
ε₀ = permittivity constant in a Vacuum= 8.85×10⁻¹² F/m

Magnitude of charge transferred between a carpet and a shoe is 4.4×10⁻⁷ Coulomb.
<h2>
Answer:</h2>
<em>Hello, </em>
<h3><u>QUESTION)</u></h3>
According to the second Newton's Law,
<em>✔ We have : F = m x a ⇔ m = F/a </em>
The mass of the object is therefore 200 kg.
Given that:
Energy of bulb (Work ) = 30 J,
Time (t) = 3 sec
The power consumption = ?
We know that, Power can be defined as rate of doing work
Power (P) = Work(Energy supplied) ÷ time
= 30 ÷ 3
= 10 Watts
<em> The power consumption is 10 W.</em>