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They compress or expand depending on amount of pressure or depending on the temperature
<span>Net charge of the object = 0.500 ÎĽc
The charge of electron = -1.602 x 10^-19 C
Calculating the net change in the number of electrons = 0.5 x 10^-6 / -1.602 x 10^-19 = - 3.12 x 10^12
The negative sign implies the number of electrons that needs to be removed that is 3.12 x 10^12</span>
By the work-energy theorem, the total work done on the car is equal to the change in its kinetic energy:
<em>W</em> = ∆<em>K</em>
<em>W</em> = 1/2 (0.34 kg) (22.9 m/s)² - 1/2 (0.34 kg) (6.5 m/s)²
<em>W</em> ≈ 82 J
Explanation:
Given that,
The slope of the ramp, 
Mass of the box, m = 60 kg
(a) Distance covered by the truck up the slope, d = 300 m
Initially the truck moves with a constant velocity. We know that the net work done on the box is equal to 0 as per work energy theorem as :

u and v are the initial and the final velocity of the truck
(b) The work done on the box by the force of gravity is given by :

Here, 


W = -24550.13 J
(c) What is the work done on the box by the normal force is equal to 0 as the angle between the force and the displacement is 90 degrees.
(d) The work done by friction is given by :


Hence, this is the required solution.