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Alex Ar [27]
3 years ago
13

A spring of original length 3.0 cm is extended to a total length of 5.0 cm by a force of 8.0N

Physics
2 answers:
miss Akunina [59]3 years ago
8 0

Answer:

12.0N

Explanation:

This problem is solved using Hooke's law which states that the extension or compression experienced by an elastic material is proportional the the force or load applied provided that the elastic limit is not exceeded.

F=ke..................(1)

where F is the force applied, k is the elastic constant and e is the extension of the material.

e=l_1-l_o..................(2)

were l_o is the original length of the material and l_1 is its total length after extension.

Given;

F = 8.0N

l_o=3cm\\l_1=5cm\\k=?

therefore,

e=5-3\\e=2cm

substituting all necessary values into equation (1), we get;

8=k*2\\k=\frac{8}{2}\\k=4N/cm

The force required to give the spring a total length of 6cm is thus calculated;

in this case,

l_1=6cm\\therefore\\e=6-3\\e=3cm

hence F is given as follows;

F=(4N/cm) *3cm\\F=12.0N

hjlf3 years ago
6 0
4848484 5 5 5 5 5  =++++
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Answer:

230 m/s northeast, 1.8 m/s up

Explanation:

204 kilometres = 204000 metres

15.0 minutes = 900 seconds

Velocity = Distance / Time

= 204000 / 900

= 230 m/s northeast (to 2 sf.)

1.6km = 1600 metres

Velocity = 1600 / 900

= 1.8 m/s up (to 2 sf.)

Read more on Brainly.com - brainly.com/question/13863590#readmore

5 0
3 years ago
Read 2 more answers
A 50.-kilogram rock rolls off the edge of a cliff. if it is traveling at a speed of 24.2 m/s when it hits the ground, what is th
ElenaW [278]

The correct answer to the question is : 29.88 m.

EXPLANATION :

As per the question, the mass of the rock m = 50 Kg.

The rock is rolling off the edges of the cliff.

The final velocity of the rock when it hits the ground v = 24 .2 m/s.

Let the height of the cliff is h.

The potential energy gained by the rock at the top of the cliff = mgh.

Here, g is known as acceleration due to gravity, and g = 9.8\ m/s^2

When the rock rolls off the edge of the cliff, the potential energy is converted into kinetic energy.

When the rock hits the ground, whole of its potential energy is converted into its kinetic energy.

The kinetic energy of the rock when it touches the ground is given as -

                Kinetic energy K.E = \frac{1}{2}mv^2.

From above we know that -

   Kinetic energy at the bottom of the cliff = potential energy at a height h

                 \frac{1}{2}mv^2=\ mgh

                ⇒ v^2=\ 2gh

                ⇒ h=\ \frac{v^2}{2g}

                ⇒ h=\ \frac{(24.2)^2}{2\times 9.8}

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5 0
3 years ago
Write a linear equation that expresses the relationship between the temperature in degrees Celsius (C) and degrees Fahrenheit (F
UkoKoshka [18]

Answer:

\displaystyle F=\frac{9}{5}C+32

\displaystyle C=\frac{5}{9}(F-32)

Explanation:

<u>Temperature Units Conversion </u>

The conversion formula between Celsius and Fahrenheit temperature scales is well-known. But we'll use the provided data to derive the formula. Let's model the relationship between Fahrenheit (F) and Celsius (C) as a linear function like

F=mC+b

Where m and b must be computed according to the pair of conditions given. The values for each temperature scale are (C,F)=(0,32) and (100,212). Replacing the first value

32=m\times 0+b

It means that  

b=32

By using the second point

212=m\times 100+32

Solving for m

\displaystyle m=\frac{212-32}{100}=\frac{180}{100}

Simplifying

\displaystyle m=\frac{9}{5}

So, the conversion formula is

\displaystyle F=\frac{9}{5}C+32

Which is the widely known formula for temperature conversion

Solving for C, we get the inverse relation

\boxed{\displaystyle C=\frac{5}{9}(F-32)}

3 0
3 years ago
An alternating source drives a series RLC circuit with an emf amplitude of 6.34 V, at a phase angle of +32.6°. When the potentia
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Answer:

V=-8.35v

Explanation:

Pls see attached file

6 0
3 years ago
Five men push a stalled car with an average force of 400 N per person. Find the mass of the
timama [110]

The mass of the car is 2000 kg

Explanation:

We can solve this problem by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

In this problem, we have:

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Each person applies a force of 400 N, and there are five men, so the total force applied is

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Therefore, the mass of the car is:

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Learn more about Newton's second law of motion:

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