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Kisachek [45]
3 years ago
5

Hat is the processes called when matter, that is a liquid, transforms into a gas?

Physics
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

vaporization ,( Evaporation)

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What type of relationship is shown in the graph
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A linear, positive relationship

Explanation:

The graph is a line, so it is linear and the slope is positive, so it is positive...

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The urethra extends from the:
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From the bladder and goes through the male genitalia.
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A brick mason builds a simple machine to lift bricks from the ground up to the second story of a building. The machine requires
Iteru [2.4K]

Answer: A MA = 0.048

Explanation: 35 divided by 735 is equal to 0.048

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3 years ago
Two students hear the same sound and their eardrums receive the same power from the sound wave. The sound intensity at the eardr
Margaret [11]

Answer:

a. d₁/d₂ = 1.09 b. 0.054 mW

Explanation:

a. What is the ratio of the diameter of the first student's eardrum to that of the second student?

We know since the power is the same for both students, intensity I ∝ I/A where A = surface area of ear drum. If we assume it to be circular, A = πd²/4 where r = radius. So, A ∝ d²

So, I ∝ I/d²

I₁/I₂ = d₂²/d₁² where I₁ = intensity at eardrum of first student, d₁ = diameter of first student's eardrum, I₂ = intensity at eardrum of second student, d₂ = diameter of second student's eardrum.

Given that I₂ = 1.18I₁

I₂/I₁ = 1.18

Since I₁/I₂ = d₂²/d₁²

√(I₁/I₂) = d₂/d₁

d₁/d₂ = √(I₂/I₁)

d₁/d₂ = √1.18

d₁/d₂ = 1.09

So, the ratio of the diameter of the first student's eardrum to that of the second student is 1.09

b. If the diameter of the second student's eardrum is 1.01 cm. how much acoustic power, in microwatts, is striking each of his (and the other student's) eardrums?

We know intensity, I = P/A where P = acoustic power and A = area = πd²/4

Now, P = IA

= I₂A₂

= I₂πd₂²/4

= 1.18I₁πd₂²/4

Given that I₁ = 0.58 W/m² and d₂ = 1.01 cm = 1.01 × 10⁻² m

So, P = 1.18I₁πd₂²/4

= 1.18 × 0.58 W/m² × π × (1.01 × 10⁻² m)²/4

= 0.691244π × 10⁻⁴ W/4 =

2.172 × 10⁻⁴ W/4

= 0.543 × 10⁻⁴ W

= 0.0543 × 10⁻³ W

= 0.0543 mW

≅ 0.054 mW

3 0
3 years ago
A racetrack curve has radius 70.0 m and is banked at an angle of 12.0 ∘. The coefficient of static friction between the tires an
zubka84 [21]

Answer:

See attachment below

Explanation:

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