Answer: Option (d) is the correct answer.
Explanation:
An orbital is defined as the energy shell which can contain a maximum of two electrons with opposite spins.
A wave like behavior of an electron is determined by an orbital and basically an orbital acts like a mathematical function.
For example, in a p-sub shell the orbitals present are
,
and
.
Therefore, we can conclude that orbitals are defined by energy level.
Answer : The molarity of solution is, 1.73 mole/L
Explanation :
The relation between the molarity, molality and the density of the solution is,
where,
![d=M[\frac{1}{m}+\frac{M_b}{1000}]](https://tex.z-dn.net/?f=d%3DM%5B%5Cfrac%7B1%7D%7Bm%7D%2B%5Cfrac%7BM_b%7D%7B1000%7D%5D)
d = density of solution = 
m = molality of solution = 2.41 mol/kg
M = molarity of solution = ?
= molar mass of solute (toluene) = 92 g/mole
Now put all the given values in the above formula, we get the molality of the solution.
![0.876g/ml=M\times [\frac{1}{2.41mol/kg}+\frac{92g/mole}{1000}]](https://tex.z-dn.net/?f=0.876g%2Fml%3DM%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2.41mol%2Fkg%7D%2B%5Cfrac%7B92g%2Fmole%7D%7B1000%7D%5D)

Therefore, the molarity of solution is, 1.73 mole/L
The magnesium atom looses two electrons which are accepted by each of the fluorine atoms. (Option D).
<h3>What is an ionic bond?</h3>
An ionic bond is formed when two ions are formed by the loss or gain electrons. In this case, magnesium has to loose two electrons while fluorine will gain two electrons.
Thus, the correct steps in the formation of an ionic bond between these atoms are A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion (Option D).
Learn more about ionic bond:brainly.com/question/11527546
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Answer:
7.96g, 33.79%
Explanation:
I'll try my best to explain the entire process behind this question ;)
From the question, you can write the reaction

Now, there are a few reasons it is like this. Oxygen is a diatomic element, meaning it doesn't and can't exist as just O. It exists as O₂. To balance, this, double the amount of water and hydrogen so there is an equal amount of each element on both sides of the reaction (4 H's, 2 O's on the reactant side, and 4 H's, 2 O's on the product side).
From this we can get a mole-to-mole ratio.
Onto the stoichiometry. Our goal in this is to convert from grams of water to grams of hydrogen, and we do so with a mole to mole ratio.

Basically, what I did was divide by water's molar mass to get moles of water, multiplied by the mole-to-mole ratio (2:2) to get moles of H2, and then multiplied by H2's molar mass to get what should be the amount of H2 produced by the reaction.
For percent yield, you can calculate it is such:

Plug the numbers in:

So, the percent yield is 33.79%