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DENIUS [597]
3 years ago
7

What is the volume of 1.25 M hydrochloric acid required to react completely with 45.0 mL of 0.500 M Ba(OH)2?

Chemistry
2 answers:
AveGali [126]3 years ago
7 0

Answer:

36.0 mL

Explanation:

First, write the balanced reaction.

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

Calculate the moles of Ba(OH)₂:

0.500 mol/L × 0.0450 L = 0.0225 mol Ba(OH)₂

Use stoichiometry to find moles of HCl:

0.0225 mol Ba(OH)₂ × (2 mol HCl / mol Ba(OH)₂) = 0.0450 mol HCl

Now calculate the volume needed at the given concentration.

0.0450 mol HCl × (1 L / 1.25 mol) = 0.0360 L HCl

You need 36.0 mL of 1.25 M HCl.

AVprozaik [17]3 years ago
4 0

Answer:

36.0 mL

Explanation:

The volume of 1.25 M hydrochloric acid required to react completely with 45.0 mL of 0.500 M Ba(OH)2 is 36.0 mL.

You would use the following equation to solve this:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

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Orbitals are defined by which term?
emmasim [6.3K]

Answer: Option (d) is the correct answer.

Explanation:

An orbital is defined as the energy shell which can contain a maximum of two electrons with opposite spins.

A wave like behavior of an electron is determined by an orbital and basically an orbital acts like a mathematical function.

For example, in a p-sub shell the orbitals present are p_{x}, p_{y} and p_{z}.

Therefore, we can conclude that orbitals are defined by energy level.

6 0
4 years ago
solution is 2.41 molal toluene (C 7H 8, 92 g/mol) in benzene (C 6H 6, 78 g/mol); i.e. consider toluene the solute, benzene the s
inn [45]

Answer : The molarity of solution is, 1.73 mole/L

Explanation :

The relation between the molarity, molality and the density of the solution is,

where,

d=M[\frac{1}{m}+\frac{M_b}{1000}]

d = density of solution  = 0.876g/cm^3=0.876g/mL

m = molality of solution  = 2.41 mol/kg

M = molarity of solution  = ?

M_b = molar mass of solute (toluene) = 92 g/mole

Now put all the given values in the above formula, we get  the molality of the solution.

0.876g/ml=M\times [\frac{1}{2.41mol/kg}+\frac{92g/mole}{1000}]

M=1.73mol/L

Therefore, the molarity of solution is, 1.73 mole/L

7 0
3 years ago
These diagrams show two atoms of fluorine and an atom of magnesium.
Diano4ka-milaya [45]

The magnesium atom looses two electrons which are accepted by each of the fluorine atoms. (Option D).

<h3>What is an ionic bond?</h3>

An ionic bond is formed when two ions are formed by the loss or gain electrons. In this case, magnesium has to loose two electrons while fluorine will gain two electrons.

Thus, the correct steps in the formation of an ionic bond between these atoms are A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion (Option D).

Learn more about ionic bond:brainly.com/question/11527546

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6 0
2 years ago
Counting atoms and balancing....please help :)
Tresset [83]

Answer:

3H20 - 6

3NH4OH - 15

4Ca(C2H3O2)2 - 24

Explanation:

Not so sure but I tried

5 0
3 years ago
I really can’t do this don’t understand it
masya89 [10]

Answer:

7.96g, 33.79%

Explanation:

I'll try my best to explain the entire process behind this question ;)

From the question, you can write the reaction

2H_2O(l)->2H_2(g)+O_2(g)

Now, there are a few reasons it is like this. Oxygen is a diatomic element, meaning it doesn't and can't exist as just O. It exists as O₂. To balance, this, double the amount of water and hydrogen so there is an equal amount of  each element on both sides of the reaction (4 H's, 2 O's on the reactant side, and 4 H's, 2 O's on the product side).

From this we can get a mole-to-mole ratio.

Onto the stoichiometry. Our goal in this is to convert from grams of water to grams of hydrogen, and we do so with a mole to mole ratio.

71.0gH_2O*\frac{1molH_2O}{18.02g} *\frac{2molH_2}{2molH_2O}* \frac{2.02g}{1molH_2}\\\\ =7.96gH_2

Basically, what I did was divide by water's molar mass to get moles of water, multiplied by the mole-to-mole ratio (2:2) to get moles of H2, and then multiplied by H2's molar mass to get what should be the amount of H2 produced by the reaction.

For percent yield, you can calculate it is such:

\frac{Actual}{Theoretical}*100

Plug the numbers in:

\frac{2.69g}{7.96g}*100\\\\ =33.79%

So, the percent yield is 33.79%

3 0
3 years ago
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