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Dmitriy789 [7]
3 years ago
6

The prefix himbo-means heap : true false

Chemistry
1 answer:
Molodets [167]3 years ago
6 0
False the definition is an attractive but unintelligent man.
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What can make this balanced by adding coefficients<br><br> CH4+O2 H2O+ CO2
Ugo [173]
CH4+2O2=> 2H2O+CO2

C- 1 on both sides
H- 4 on both sides
O - 4 on both sides
6 0
3 years ago
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How does the property of density help to identify substances?
Mashutka [201]

Answer:

Density can be useful in identifying substances. It is also a convenient property because it provides a link (or conversion factor) between the mass and the volume of a substance. Mass and volume are extensive (or extrinsic) properties of matter - they depend on amount.

Explanation:

4 0
4 years ago
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What influences attraction for electrons?
Troyanec [42]
If you are talking about bonds they are influenced by electronegativity and how many valence electrons they have.
7 0
3 years ago
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Write the equilibrium constant expression Kc for the following reaction.2H20(g) ---------&gt; O2(g) + 2H2(g) &lt;---------Do not
Komok [63]

Answer:

K_c\text{ = }\frac{[O_2][H_2]\placeholder{⬚}^2}{[H_2O]\placeholder{⬚}^2}

Explanation:

Here, we want to write the equilibrium constant expression

To write this, we raise the concentrations of the reactants and products to the coefficient before them. These concentrations are represented by square brackets in which the chemical formula of the compound is placed

We place the representation of the products over that of the reactants

We have the expression written as follows:

K_c\text{ =  }\frac{[H_2]\placeholder{⬚}^2[O_2]}{[H_2O]\placeholder{⬚}^2}

7 0
1 year ago
A. Phenol (C6H5OH) is an aromatic compound and a colourless liquid widely used in household products
Olin [163]

Because there are 2 Cl on the left, we will put a coefficient 2in front of HCl on the right side to balance out the Cl. This would result in an unequal amount of H, with 6 on the right side and 7 in the left, so we have to put a coefficient of 2 in front of C6H5OH and C6H4OH on both sides to balance out the H. By doing this, we would obtain an equal amount of H on both sides. The Carbon is already balanced, and so is the Oxygen.

8 0
3 years ago
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