The prefix himbo-means heap : true false

Two of the seven different pea traits examined by Mendel involved genes that we now know are linked. Knowing this, can you expla

ser-zykov [4K]

Answer:: Mendel studied how traits are been passed from parents to offspring using seven features in peas, including height, flower color, seed color, and seed shape. To do this he divided the pea plant into short height and tall height. From this experiment he proposed a principle called independent assortment, which describes how different genes independently separate from one another when reproductive cells develop. Though this experiment was studied using gene formation in prokaryotic cell.

This principle of independent assortment is also seen in eukaryotic cells during meiosis.

Mendel proposed this principle because during cell formation of the offspring, each individual Gene from the parents will first separate to stand on its own before cross linking up together, which made the offspring look different from the parents. The principle of independent assortment does not criticize gene linkage, it only highlight how gene in the garments of the parents forms offspring, by sperating to assort independently.

4 0

3 years ago

How is the separation of dna like a zipper

Sedbober [7]

The two strands must be separated like the two sides of a zipper, by breaking the weak hydrogen bonds that link the paired bases.

<u>Explanation:</u>

A double helix structure formed by two polypeptide chains is separated like the two sides of a zipper. A zipper is formed by breaking the weak hydrogen bonds that link the paired bases. During replication, an enzyme "Helicase" travels down the DNA and splits the chain and it forms 2 separate strands.

The two DNA strand which has the same sequence must be separated like the two sides of a zipper by breaking weak hydrogen bases. During base pair-rule, the strand are unzipped and each strands is copied.

3 0

3 years ago

Scoring Scheme: 3-3-2-1 Part I. How many mL of 6 M NaOH stock solution should be used to prepare the 500 mL of 0.2 M NaOH? Pleas

Orlov [11]

Answer : The volume of 6M NaOH stock solution is, 16.7 mL

Explanation :

To calculate the volume of NaOH stock solution, we use the equation given by neutralization reaction:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of NaOH stock solution.

$M_2\text{ and }V_2$ are the molarity and volume of NaOH.

We are given:

$M_1=6M\\V_1=?\\M_2=0.2M\\V_2=500mL$

Putting values in above equation, we get:

$6M\times V_1=0.2M\times 500mL\\\\V_1=16.7mL$

Thus, the volume of 6M NaOH stock solution is, 16.7 mL

4 0

3 years ago

Under which of the following conditions would a chemical reaction most likely proceed at the fastest rate?

Valentin [98]

<h2>Answer:</h2>

Option A is correct

Adding an enzyme to decrease the activation energy of the reaction

<h2>Explanation:</h2>

Enzymes are the biological catalyst. They are proteins in nature. They are naturally found in humans,animals,micro-organisms,plants etc. They catalyze the chemical reactions by lowering activation energy and without being consumed in it.

6 0

3 years ago

Read 2 more answers

The reaction for photosynthesis producing glucose sugar and oxygen gas is:

Anvisha [2.4K]

<u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

So, in this case, the balanced reaction is:

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:

CO₂: 6 moles
H₂O: 6 moles
C₆H₁₂O₆: 1 mole
O₂: 6 moles

So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:

$moles of CO_{2} =2.20 grams*\frac{1 mole}{44.01 grams}$

moles of CO₂= 0.05 moles

Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?

$moles of C_{6} H_{12} O_{6} =\frac{0.05moles of CO_{2} *1 mole of C_{6} H_{12} O_{6}}{6moles of CO_{2}}$

moles of C₆H₁₂O₆= 8.33*10⁻³

Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:

$mass of glucose =8.33*10^{-3} moles*\frac{180.18 grams}{1 mole}$

<em>mass of glucose= 1.5 grams</em>

Then, <u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

5 0

3 years ago