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2 years ago

Counting atoms and balancing....please help :)

Chemistry

1 answer:

Tresset [83]2 years ago

5 0

Answer:

3H20 - 6

3NH4OH - 15

4Ca(C2H3O2)2 - 24

Explanation:

Not so sure but I tried

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Put the following elements into five pairs of elements that have similar chemical reactivity: F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

kirill115 [55]

Explanation:

Given elements:

F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Elements with the same chemical reactivity will belong to the same group on the periodic table. This implies that elements in the same column will have the same reactivity;

Li and Rb are both alkali metals in group 1

Ca and Sr are both alkali earth metals in group 2

F and Br are halogens in group 7

O and S are group 6 elements

P and Sb are both in group 5 on the periodic table

So these groupings show elements with the same chemical properties.

7 0

2 years ago

The electron configuration of an element is shown below.

g100num [7]

Answer:

helium family or neon family

Explanation:

you can use p

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3 years ago

In the event that you are exposed to infectious materials by being accidentally stuck with a used needle, you should report it t

bagirrra123 [75]

Use a tourniquet to reduce the rate of it spreading

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3 years ago

Read 2 more answers

A high jumper jumps 2.09m. If the jumper has a mass of 72kg, what is his gravitational potential energy at the highest point of

Furkat [3]

Si Ko alam hehehehe sorrry men

4 0

3 years ago

14. A piece of titanium at 100.0°C was dropped into 50.0 g of water at 20.0°C. The final temperature of the system was 22.6°C. W

Gemiola [76]

Answer:

$m_{Ti}=13.0g$

Explanation:

Hello,

In this case, based on the given, we can infer that as titanium is hot and water cold, it cools down whereas the water is heated up, therefore, in terms of heat, we have that the heat lost by the titanium is gained by the water:

$-Q_{Ti}=Q_{H_2O}$

That in terms of mass, specific heat and temperatures is:

$-m_{Ti}Cp_{Ti}(T_2-T_{Ti})=m_{H_2O}Cp_{H_2O}(T_2-T_{H_2O})$

In such a way, for computing the mass of titanium, considering the heat capacity of water 4.18 J/g°C, we have:

$m_{Ti}=\frac{m_{H_2O}Cp_{H_2O}(T_2-T_{H_2O})}{-Cp_{Ti}(T_2-T_{Ti})} \\\\m_{Ti}=\frac{50.0g*4.18\frac{J}{g\°C}(22.6-20.0)\°C}{-0.54\frac{J}{g\°C}*(22.6-100.0)\°C} \\\\m_{Ti}=13.0g$

Regards.

8 0

3 years ago