Mg (s) + 2 HCl (aq) -> MgCl2 (aq) + H2 (g)
1) Number of mols of HCl, n
n = 6.3 L * 4.5 mol/L = 28.35 mol
2) ratio: 2 mol HCl / 1 mol Mg = 28.35 mol HCl / x mol Mg
x = 28.35 mol HCL * 1 mol Mg / 2 mol HCL = 14.175 mol Mg
3) Convert mol to mass using atomic mass of Mg
14.175 mol Mg * 24.3 g Mg / mol Mg = 344. 45 g
Answer: 344.45 g
Sp2 hybridization forms 1 sigma bond and 1 pi bond.
Answer:
Classifying stars according to their spectrum is a very powerful way to begin to understand how they work. As we said last time, the spectral sequence O, B, A, F, G, K, M is a temperature sequence, with the hottest stars being of type O (surface temperatures 30,000-40,000 K), and the coolest stars being of type M (surface temperatures around 3,000 K). Because hot stars are blue, and cool stars are red, the temperature sequence is also a color sequence. It is sometimes helpful, though, to classify objects according to two different properties. Let's say we try to classify stars according to their apparent brightness, also. We could make a plot with color on one axis, and apparent brightness on the other axis, like this:
Explanation:
Answer:
Explanation:
Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:
Where 
is Henry's law constant.
Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.
Given initially:
Also, at sea level, we have an atmospheric pressure of:
Given mole fraction:
According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:
Then the equation becomes:
Solve for :
Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:
Apply Henry's law using the constant we found:
In order to find out the ranking of ions basicity, check the
pKa values of each ions. The principle that you need to remember is that the
stronger the acid the weaker the corresponding conjugate base. The pKa dictates
acid value of the compound. The answer would be CH3NH, CH3O-, and CH3CH2-.
