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stellarik [79]
3 years ago
6

Magnesium and iron are metallic elements. How does a mole of magnesium compare with a mole of iron?

Chemistry
2 answers:
Simora [160]3 years ago
6 0

One mole of any substance is equal to Avogadro’s number, 6.023 x 10²³  

A mole of magnesium = a mole of iron = Avogadro’s number, 6.023 x 10 ²³

One mole of any element contains 6.023 x 10²³ number of atoms.  

One mole of any substance contains 6.023 x 10²³ number of atoms, molecules, ions, or formula units.

Dennis_Churaev [7]3 years ago
5 0
<span>They both have the same number of atoms. The molar mass of CO2 is 44.01 g/mol.</span>
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A chemical change in which a single compound breaks down into two or more products is which of the following?
Liono4ka [1.6K]

Answer:

a. Decomposition.

Explanation:

A combination reaction is a reaction where two or more elements or compounds combine to form a single compound. Such reactions may be represented by equations of the following form: X + Y ⇒ XY.

  • Decomposition reactions are a type of chemical reaction that involves breaking down a compound into smaller compounds or individual elements.
  • A single-displacement reaction, also known as a single-replacement reaction, is a reaction by which one element replaces other element in a compound.
  • A double displacement reaction, also known as a double replacement reaction or metathesis, is a type of chemical reaction where two compounds react, and the positive ions (action) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.

Hence, the answer is a decomposition reaction.

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3 years ago
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It is Z1 and Z4 only... Answer is number 1
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3 years ago
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What branch of chemistry studies the flow of electrons?
grin007 [14]

Answer:

Your answer is B, Electrochemistry!

Explanation:

This is the part of chemistry that studies the chemical process in which electrons flow. This flow is called electricity. Electricity is generated by the flow of electrons, from one element to another element. This reaction is called oxidation reduction.

6 0
2 years ago
Consider the reaction: 2BrF3(g) --&gt; Br2(g) + 3F2(g)
riadik2000 [5.3K]

Answer : The entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition is 217.68 J/K

Explanation :

The given balanced reaction is,

2BrF_3(g)\rightarrow Br_2(g)+3F_2(g)

The expression used for entropy change of reaction (\Delta S^o) is:

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{Br_2}\times \Delta S_f^0_{(Br_2)}+n_{F_2}\times \Delta S_f^0_{(F_2)}]-[n_{BrF_3}\times \Delta S_f^0_{(BrF_3)}]

where,

\Delta S^o = entropy change of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

\Delta S_f^0_{(Br_2)} = 245.463 J/mol.K

\Delta S_f^0_{(F_2)} = 202.78 J/mol.K

\Delta S_f^0_{(BrF_3)} = 292.53 J/mol.K

Now put all the given values in this expression, we get:

\Delta S^o=[1mole\times (245.463J/K.mole)+3mole\times (202.78J/K.mole)}]-[2mole\times (292.53J/K.mole)]

\Delta S^o=268.74J/K

Now we have to calculate the entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition.

From the reaction we conclude that,

As, 2 moles of BrF_3 has entropy change = 268.74 J/K

So, 1.62 moles of BrF_3 has entropy change = \frac{1.62}{2}\times 268.74=217.68J/K

Therefore, the entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition is 217.68 J/K

3 0
4 years ago
In a data set, the number that appears the most is called the ( ).
scZoUnD [109]

Answer:

Mode

Explanation:

The mode is the number that appears most frequently in a data set. A set of numbers may have one mode, more than one mode, or no mode at all. Other popular measures of central tendency include the mean, or the average (mean) of a set, and the median, the middle value in a set.

4 0
4 years ago
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