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stellarik [79]
3 years ago
6

Magnesium and iron are metallic elements. How does a mole of magnesium compare with a mole of iron?

Chemistry
2 answers:
Simora [160]3 years ago
6 0

One mole of any substance is equal to Avogadro’s number, 6.023 x 10²³  

A mole of magnesium = a mole of iron = Avogadro’s number, 6.023 x 10 ²³

One mole of any element contains 6.023 x 10²³ number of atoms.  

One mole of any substance contains 6.023 x 10²³ number of atoms, molecules, ions, or formula units.

Dennis_Churaev [7]3 years ago
5 0
<span>They both have the same number of atoms. The molar mass of CO2 is 44.01 g/mol.</span>
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According to the below equation, how many moles of SO2 are required to generate 1.43×1024 water molecules?
podryga [215]
Make sure the equation is always balanced first. (It is balanced for this question already) 6.022 x 10^23 is Avogadro’s number. In one mole of anything there is always 6.022 x 10^23 molecules, formula units, atoms. For one mol of an element/ compound use molar mass (grams).

Multiply everything on the top = 8.61x10^47
Multiple everything on bottom= 1.20x10^24
Divide top and bottom = 7.15x10^23

Answer: 7.15x10^23 mol SO2
3 0
4 years ago
In a biome there are many animals that eat one another creating a
yuradex [85]

Answer: Food Chain

Explanation: In a food chain, energy is passed from one link to another. Many organisms cannot make their own food, so rely on eah other for nourishment.

8 0
3 years ago
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What is the melting point of water?
o-na [289]
 the melting point of water is 32 degrees Fahrenheit , 0 degrees Celsius. <span />
6 0
4 years ago
The salt formed by the reaction of the weak acid hydrocyanic acid, HCN, with the strong base potassium hydroxide is
iogann1982 [59]

Answer:

2.28 × 10^-3 mol/L

Explanation:

The equation for the equilibrium is

CN^- + H2O ⇌ HCN + OH^-

                    Ka = 4.9 × 10^-10

               KaKb = Kw

4.9 × 10^-10 Kb = 1.00 × 10^-14

                   Kb = (1.00 × 10^-14)/(4.9 × 10^-10) = 2.05 × 10^-5

Now, we can set up an ICE table

                     CN^- + H2O ⇌ HCN + OH^-

I/(mol/L)      0.255                     0         0

C/(mol/L)       -x                        +x        +x

E/(mol/L)  0.255 - x                   x         x

Ka = x^2/(0.255 - x) = 2.05 × 10^-5

Check for negligibility

0.255/(2.05 × 10^-5) = 12 000 > 400. ∴ x ≪ 0.255

    x^2 = 0.255(2.05 × 10^-5) = 5.20 × 10^-6

        x = sqrt(5.20 × 10^-6)    = 2.28 × 10^-3

[OH^-] = x mol/L                     = 2.28 × 10^-3 mol/L

5 0
3 years ago
Will mark as brainiest <br> Please help
Levart [38]

Answer:

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(Correct me if I am wrong)

4 0
3 years ago
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