Answer: 46.6 grams
Explanation:
Given : density of hexane = 0.660 g/ml
volume of hexane = 20 ml
Mass of hexane = 
moles of hexane =
According to stoichiometry :
2 moles of hexane reacts with 19 moles of oxygen
Thus 0.14 moles hexane will react with =
moles of oxygen
Mass of oxygen =
Thus minimum mass of oxygen required for the complete reaction of 20.0 mL of hexane is 46.6 grams.
No, Heat moves from concentrations of high to low.
Answer:
28.6
Explanation:
Step 1: Write the balanced reaction at equilibrium
CO(g) + Cl₂(g) ⟺ COCl₂(g)
Step 2: Calculate the equilibrium partial pressure (in atm) of phosgene?
We will use the expression for the pressure equilibrium constant (Kp)
Kp = pCOCl₂ / pCO × pCl₂
pCOCl₂ = Kp × pCO × pCl₂
pCOCl₂ = 1.49 × 10⁸ × 4.38 × 10⁻⁴ × 4.38 × 10⁻⁴ = 28.6
