So the whole point is that you need a abstract.
<span>Zn⁰(s) + CuSO4(aq) --> Zn²⁺SO4²⁻(aq) + Cu(s)
</span>Zn⁰ --- in free elements oxidation number is 0.
Zn²⁺SO4²⁻ ---- ionic compound , it has ion Zn²⁺, so oxidation number here is +2.
<span>The oxidation number of Zn changes from 0 to +2.</span>
Answer:
The number of atoms contained by one molecule of Iron (II) Sulfate are 6.
Explanation:
Iron (II) Sulfate is mage up of two parts. One is the Positive part which constitutes of Fe⁺² and a negative part which constitutes of a polyatomic anion i.e. SO₄²⁻. As there are four Oxygen and one sulfur atom in sulfate Ion so sulfate ion contains 5 atoms in total. Therefore, five atoms from sulfate iona dn one atom of Iron ion makes a total of 6 atoms in one molecule of Iron (II) Sulfate.
Potassium sulfite<span> (K</span>₂<span>SO</span>₃<span>)
hope this helps!</span>