1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
djverab [1.8K]
3 years ago
8

WILL GIVE BRAINLIEST! Explain how a pure metal is held together. Include a definition of a metallic bond in your explanation. Pl

ease don't copy someone else's answer!
Chemistry
2 answers:
mote1985 [20]3 years ago
8 0

Answer:

Explanation:

Metals are held together by metallic bonds. Metallic bonds consist of the attraction of the free-floating valence electrons for the positively charged metal ions. These bonds are the forces of attraction that hold metals together.

Metals are made up of closely packed cations rather than neutral atoms. The valence electrons of metal atoms can be modeled as a sea of electrons. The valence electrons are mobile and can drift freely from one part of the metal to another. Metallic bonds consist of the attraction of the free-floating valence electrons for the positively charged metal ions. These bonds are the forces of attraction that hold metals together.

vazorg [7]3 years ago
7 0

Explanation:

A chemical bond which is formed in between positively charged atoms when there is sharing of free electrons in a lattice of cations is known as a metallic bond.

In a pure metal, atoms are surrounded by free moving valence electrons which move from one part of metal to another.

Thus, we can conclude that pure metals are held together by metallic bonds due to attraction between mobile valence electrons and positively charged metal ions.


You might be interested in
g The most common position for an double bond in an unsaturated fatty acid is delta _________(fill in the number).
Stolb23 [73]

Answer:

The most common position for an double bond in an unsaturated fatty acid is delta 9 (Δ⁹)

Explanation:

Unsaturated fatty acids are carboxylic acids which contains one or more double bonds. The chain length as well as the number of double bonds is written separated by a colon. The positions of the double bonds are specified starting from the carboxyl carbon, numbered as 1, by superscript numbers following a delta (Δ). For example, an 18-carbon fatty acid containing a  single double bond between carbon number 9 and 10 is written as 18:1(Δ⁹).

In most monounsaturated fatty acids, the double bond is between C-9 and C-10 (Δ⁹), and the other double bonds of polyunsaturated fatty acids are generally Δ¹² and Δ¹⁵. This positioning is due to the nature of the biosynthesis of fatty acids. In the mammalian hepatocytes, double bonds are introduced easily into fatty acids at the Δ⁹ position, but cannot introduce additional double bonds between C-10 and the methyl-terminal end. However, plants are able to introduce these additional double bonds at the  Δ¹² and Δ¹⁵ positions.

5 0
4 years ago
Plz say if it is a b c or d on both
Digiron [165]

Answer:

whats both

Explanation:

7 0
3 years ago
Read 2 more answers
The combustion reaction described in part (b) occurred in a closed room containing 5.56 10g of air
vagabundo [1.1K]

Answer:

Explanation:

Combustion reaction is given below,

C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)

Provided that such a combustion has a normal enthalpy,

ΔH°rxn = -1270 kJ/mol

That would be 1 mol reacting to release of ethanol,

⇒ -1270 kJ of heat

Now,

0.383 Ethanol mol responds to release or unlock,

(c) Determine the final temperature of the air in the room after the combustion.

Given that :

specific heat c = 1.005 J/(g. °C)

m = 5.56 ×10⁴ g

Using the relation:

q = mcΔT

- 486.34 =  5.56 ×10⁴  × 1.005 × ΔT

ΔT= (486.34 × 1000 )/5.56×10⁴  × 1.005

ΔT= 836.88 °C

ΔT= T₂ - T₁

T₂ =  ΔT +  T₁

T₂ = 836.88 °C + 21.7°C

T₂ = 858.58 °C

Therefore, the final temperature of the air in the room after combustion is 858.58 °C

7 0
4 years ago
How many moles are present in 60 grams of hydrochloric acid, HClHClH?
Brilliant_brown [7]

Answer:

C 60

Explanation:

5 0
3 years ago
Assume that the NO, concentration in a house with a gas stove is 150 pg/m°. Calculate the equivalent concentration in ppm at STP
jok3333 [9.3K]

Explanation:

It is known that for NO_{2}, ppm present in 1 mg/m^{3} are as follows.

                      1 \frac{mg}{m^{3}} = 0.494 ppm

So, 150 pg/m^{3} = \frac{150}{1000} mg/m^{3}

                       = 0.15 mg/m^{3}

Therefore, calculate the equivalent concentration in ppm as follows.

             0.15 \times 0.494 ppm

              = 0.074 ppm

Thus, we can conclude that the equivalent concentration in ppm at STP is 0.074 ppm.  

4 0
3 years ago
Other questions:
  • En invierno, nieva en la cordillera.
    5·1 answer
  • Please explain this !!!
    5·1 answer
  • NEED THIS NOW!! ON THE QUIZ Which type of energy refers to the sum of potential and kinetic energies in the particles of a subst
    11·2 answers
  • What is the molar mass of Fe3(PO4)2?
    14·1 answer
  • How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)
    11·1 answer
  • what is a geyser? nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
    5·1 answer
  • Describe one of the major differences between oceanic crust and continental crust.
    9·1 answer
  • If 15.7 grams of A1203 are produced, how many grams of iron (Fe) were
    15·1 answer
  • Part 1. A chemist reacted 18.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
    5·1 answer
  • Buenos días amiga quiero hablar
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!