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djverab [1.8K]
3 years ago
8

WILL GIVE BRAINLIEST! Explain how a pure metal is held together. Include a definition of a metallic bond in your explanation. Pl

ease don't copy someone else's answer!
Chemistry
2 answers:
mote1985 [20]3 years ago
8 0

Answer:

Explanation:

Metals are held together by metallic bonds. Metallic bonds consist of the attraction of the free-floating valence electrons for the positively charged metal ions. These bonds are the forces of attraction that hold metals together.

Metals are made up of closely packed cations rather than neutral atoms. The valence electrons of metal atoms can be modeled as a sea of electrons. The valence electrons are mobile and can drift freely from one part of the metal to another. Metallic bonds consist of the attraction of the free-floating valence electrons for the positively charged metal ions. These bonds are the forces of attraction that hold metals together.

vazorg [7]3 years ago
7 0

Explanation:

A chemical bond which is formed in between positively charged atoms when there is sharing of free electrons in a lattice of cations is known as a metallic bond.

In a pure metal, atoms are surrounded by free moving valence electrons which move from one part of metal to another.

Thus, we can conclude that pure metals are held together by metallic bonds due to attraction between mobile valence electrons and positively charged metal ions.


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Write a balanced molecular reaction for the hydrogenation of ethyne to the saturated alkane.
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A helium balloon contains 0.40 g of helium. given the molecular weight of helium is 4.0 g/mol, how many moles of helium does it
Rasek [7]

Answer is 0.10 mol.


<em>Explanation;</em>


n = m/M


Where n is number of moles (mol), m is the mass of substance (g) and M is the molar mass of the substance (g/mol).


n = ?

m = 0.40 g

M = 4.0 g/mol


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n = 0.40 g /4.0 g/mol

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8 0
3 years ago
what is the amount of heat energy released when 50.0 grams of water is cooled from 20.0 degrees Celcius to 10.0 degrees celcius
andre [41]

Answer:

The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to  - 2093 J.

Explanation:

Given data:

Mass of water = 50 g

Initial temperature= T1 = 20°C

Final temperature= T2 = 10°C

Specific heat of water= c = 4.186 J/g. °C

Amount of heat released = Q= ?

Solution:

Formula:

Q = m. C.  ΔT

ΔT = T2 - T1

ΔT = 10°C - 20°C

ΔT = -10°C

Now we will put the values in formula.

Q = m. C.  ΔT

Q = 50 g .  4.186 J/g. °C . -10°C

Q =  - 2093 J

The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to  - 2093 J.

6 0
3 years ago
Read 2 more answers
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