Write a net ionic equation for the reaction between mno4- and fe2+ in acid solution

1 answer:

6 0

Answer : The complete net ionic reaction between $MnO _{4} ^{-}$ and $Fe ^{2+}$ in an acid solution, can be written as :-

$MnO _{4} ^{-} + 5Fe ^{2+} + 8 H ^{+} ----\ \textgreater \ Mn ^{2+} + 5 Fe^{3+} + 4 H _{2}O.$

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Visible light has an average wavelength of 550 nm. How much energy would be in this wavelength of light? 5 x 10-19

beks73 [17]

Answer:

E = 3.6×10⁻¹⁹ J

Explanation:

Given data:

Wavelength = 550 nm (550 ×10⁻⁹ nm)

Energy of wave = ?

Solution:

Formula:

E = h c/λ

c = 3×10⁸ m/s

h = 6.63×10⁻³⁴ Js

Now we will put the values in formula.

E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s /550 ×10⁻⁹ nm

E = 19.89×10⁻²⁶ J.m /550 ×10⁻⁹ nm

E = 0.036×10⁻¹⁷ J

E = 3.6×10⁻¹⁹ J

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2 years ago

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skad [1K]

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3 years ago

Give the product of the reaction of excess benzene (2 equivalents) with dichloromethane and alcl3.

SOVA2 [1]

Hello!

The product of the reaction of excess benzene with dichloromethane is diphenylmethane.

The reaction that benzene undergoes with dichloromethane is a Friedel-Crafts Alkylation, in which firstly Benzene is alkylated to Benzyl Chloride, and after that, the Benzyl Chloride reacts with another equivalent of Benzene to form the compound Diphenylmethane. The Reaction Scheme is shown in the image below:

Have a nice day!