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Flauer [41]
2 years ago
11

How many grams are in 1.23 x 1020 atoms of arsenic?

Chemistry
1 answer:
Alina [70]2 years ago
6 0

Given the data from the question, the mass of arsenic that contains 1.23×10²⁰ atoms is 0.0153 g

<h3>Avogadro's hypothesis </h3>

6.02×10²³ atoms = 1 mole of arsenic

But

1 mole of arsenic = 75 g

Thus, we can say that:

6.02×10²³ atoms = 75 g of arsenic

<h3>How to determine the mass that contains 1.23×10²⁰ atoms</h3>

6.02×10²³ atoms = 75 g of arsenic

Therefore,

1.23×10²⁰ atoms = (1.23×10²⁰ × 75) / 6.02×10²³ atoms)

1.23×10²⁰ atoms = 0.0153 g of arsenic

Thus, 1.23×10²⁰ atoms is present in 0.0153 g of arsenic

Learn more about Avogadro's number:

brainly.com/question/26141731

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V1T2 = V2T1 is an expression of who’s law
Andru [333]

<u>Answer:</u>

It is the expression of Charles' Law.

<u>Explanation:</u>

The given expression V1T2 = V2T1 is the formula for the Charles' Law.

A special case of an ideal gas is named as the Charles' Law. This law applies to ideal gases only which are at constant pressure.

According to this law, the volume of a fixed mass of a gas is directly proportional to its temperature and is given by:

V1T2 = V2T1

6 0
4 years ago
Read 2 more answers
Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0
3 years ago
In a physical change, the makeup of matter is changed.<br> True or false?
Simora [160]

Answer:

false

Explanation:

because it's just a physical change, the matter won't be changed.

Hope this might help you! I don't know if this is going to be right on everything, but it's a anwser

6 0
3 years ago
Help. The answer to question 1 I didn't mean to click so please answer that as well.
Zepler [3.9K]
We have that energy=specific heat * change in temperature * mass. Thus, we have the final temperature (22) minus the initial temperature (55) to equal -33 as our change in temperature. Our specific heat is in J/g*C, so we're good with that because g stands for grams and the aluminium is measured in grams. As there are 10 grams of aluminum, we have
10*(-33)*0.902=-298 ish as our final temperature

An exothermic reaction would release energy and would therefore lose heat itself, while an endothermic reaction would absorb energy and gain heat. Therefore, losing heat would be an exothermic reaction

Feel free to ask further questions!
4 0
3 years ago
What is the change in boiling point for a 0.615m solution of Mgl2 in water?
ivanzaharov [21]

Answer :  The change in boiling point is, 0.94^oC

Explanation :

Formula used :

\Delta T_b=i\times K_f\times m

where,

\Delta T_b = change in boiling point = ?

i = Van't Hoff factor = 3 (for MgI₂ electrolyte)

K_f = boiling point constant for water = 0.51^oC/m

m = molality  = 0.615 m

Now put all the given values in this formula, we get

\Delta T_b=3\times (0.51^oC/m)\times 0.615m

\Delta T_b=0.94^oC

Therefore, the change in boiling point is, 0.94^oC

4 0
3 years ago
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