Question

How many grams are in 1.23 x 1020 atoms of arsenic?

Answer 1

Given the data from the question, the mass of arsenic that contains 1.23×10²⁰ atoms is 0.0153 g

Avogadro's hypothesis

6.02×10²³ atoms = 1 mole of arsenic

But

1 mole of arsenic = 75 g

Thus, we can say that:

6.02×10²³ atoms = 75 g of arsenic

How to determine the mass that contains 1.23×10²⁰ atoms

6.02×10²³ atoms = 75 g of arsenic

Therefore,

1.23×10²⁰ atoms = (1.23×10²⁰ × 75) / 6.02×10²³ atoms)

1.23×10²⁰ atoms = 0.0153 g of arsenic

Thus, 1.23×10²⁰ atoms is present in 0.0153 g of arsenic

Learn more about Avogadro's number:

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