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4 years ago

I need to know this answer I've worked it out but not sure

Mathematics

1 answer:

devlian [24]4 years ago

7 0

$\cfrac{r^{-3}s^5t^2}{r^2st^{-2}} = \cfrac{s^4*t^2*t^2}{r^2*r^3} =\cfrac{s^4t^4}{r^5}$

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sergeinik [125]

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answer is not possible

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3 years ago

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I NEED HELP FAST!!!!!!!!!! ⦁ Solve the equation. Describe the solution to the equation as one solution, no solution, or an infin

g100num [7]

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3 years ago

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marishachu [46]

Answer:

19.2

Step-by-step explanation:

1st Case:

4 and 5 are legs of the right triangle.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+5^2=x^2

16+25=x^2

41=x^2

x=√41

√41 is about 6.4

x=6.4

2nd Case

5 is the hypotenuse of the right triangle and 4 is the legs.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+x^2=5^2

16+x^2=25

x^2=9

x=3

Final Step

We need to multiply the two possible lengths for x. So for case 1 the length of x was 6.4 and for case two the length was 3. 6.4*3=19.2

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3 years ago

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ira [324]

Answer:

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BabaBlast [244]

Answer:

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Step-by-step explanation:

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