Question

Given the quadratic function : f(x)=x^24x-12 Find the vertex. Can you show the steps?!?

Answer 1

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ \begin{array}{llcccl} \stackrel{f(x)}{y} = & 1x^2& +4x& -12\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array} \qquad \left(-\cfrac{ b}{2 a}\quad ,\quad c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{4}{2(1)}~~,~~-12-\cfrac{4^2}{4(1)} \right)\implies (-2~~,~~-12-4)\implies (-2~~,~~-16)$