3 years ago

Find the sample standard deviation with the data 0.62, 1.05, 0.58, 1.17, 1.04, 1.37, 1.32, 0.67, 1.25 1.38, 0.86

1 answer:

4 0

$standard \: deviation \: = \sqrt{ \frac{12.5485}{11} } - (1.028) {}^{2} \\ = 0.28981$

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Answer:

Step-by-step explanation:

First calculate BD using sine ratio in Δ BCD and the exact value

sin60° = $\frac{\sqrt{3} }{2}$ , thus

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{BD}{BC}$ = $\frac{BD}{12}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2BD = 12 $\sqrt{3}$ ( divide both sides by 2 )

BD = 6 $\sqrt{3}$

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Calculate AD using the tangent ratio in Δ ABD and the exact value

tan30° = $\frac{1}{\sqrt{3} }$ , thus

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